How to find the solution to an inequality with addition - SAT Math

Absolute value problems always have two sides: one positive and one negative.

First, take the problem as is and drop the absolute value signs for the positive side: z – 3 ≥ 5. When the original inequality is multiplied by –1 we get z – 3 ≤ –5.

Solve each inequality separately to get z ≤ –2 or z ≥ 8 (the inequality sign flips when multiplying or dividing by a negative number).

We can verify the solution by substituting in 0 for z to see if we get a true or false statement. Since –3 ≥ 5 is always false we know we want the two outside inequalities, rather than their intersection.

3_w_/2 will become greater than 1 as soon as w is greater than two thirds. It will likewise become less than –1 as soon as w is less than negative two thirds. All the other options always return values between –1 and 1.

To solve this problem, add the two equations together:

The only answer choice that satisfies this equation is 0, because 0 is less than 4.

First, solve the inequality :

Since we are dealing with absolute value, must also be true; therefore:

To solve , isolate .

Divide by three on both sides.

We want to isolate the variable on one side and numbers on another side. Treat like a normal equation.

Subtract on both sides.

Divide on both sides.

We want to isolate the variable on one side and numbers on another side. Treat like a normal equation.

Subtract on both sides.

Divide on both sides. Remember to flip the sign.

We want to isolate the variable on one side and numbers on another side. Treat like a normal equation.

Subtract on both sides.

We want to isolate the variable on one side and numbers on another side. Treat like a normal equation.

We need to set-up two equations since its absolute value.

Subtract on both sides.

Divide on both sides which flips the sign.

Subtract on both sides.

Since we have the 's being either greater than or less than the values, we can combine them to get .

We want to isolate the variable on one side and numbers on another side. Treat like a normal equation.

We need to set-up two equations since it's absolute value.

Subtract on both sides.

Distribute the negative sign to each term in the parenthesis.

Add and subtract on both sides.

Divide on both sides.

We must check each answer. Let's try .

This is true therefore is a correct answer. Let's next try .

This is not true therefore is not correct.

Final answer is just .

We want to isolate the variable on one side and numbers on another side. Treat like a normal equation.

We need to set-up two equations since it's absolute value.

Subtract on both sides.

Divide on both sides.

Distribute the negative sign to each term in the parenthesis.

Add and subtract on both sides.

Divide on both sides.

We must check each answer. Let's try .

This is true therefore is a correct answer. Let's next try .

This is not true therefore is not correct.

Final answer is just .