How to find f(x) - SAT Math

Card 0 of 20

Question

Let f(x, y) = x2y2 – xy + y. If a = f(1, 3), and b = f(–2, –1), then what is f(a, b)?

Answer

f(x, y) is defined as x2y2 – xy + y. In order to find f(a, b), we will need to first find a and then b.

We are told that a = f(1, 3). We can use the definition of f(x, y) to determine the value of a.

a = f(1, 3) = 1232 – 1(3) + 3 = 1(9) – 3 + 3 = 9 + 0 = 9

a = 9

Similarly, we can find b by determining the value of f(–2, –1).

b = f(–2, –1) = (–2)2(–1)2 – (–2)(–1) + –1 = 4(1) – (2) – 1 = 4 – 2 – 1 = 1

b = 1

Now, we can find f(a, b), which is equal to f(9, 1).

f(a, b) = f(9, 1) = 92(12) – 9(1) + 1 = 81 – 9 + 1 = 73

f(a, b) = 73

The answer is 73.

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Question

Let F(x) = _x_3 + 2_x_2 – 3 and G(x) = x + 5. Find F(G(x))

Answer

F(G(x)) is a composite function where the expression G(x) is substituted in for x in F(x)

F(G(x)) = (x + 5)3 + 2(x + 5)2 – 3 = x_3 + 17_x_2 + 95_x + 172

G(F(x)) = _x_3 + _x_2 + 2

F(x) – G(x) = _x_3 + 2_x_2 – x – 8

F(x) + G(x) = _x_3 + 2_x_2 + x + 2

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Question

What is the value of xy_2(xy – 3_xy) given that x = –3 and y = 7?

Answer

Evaluating yields –6174.

–147(–21 + 63) =

–147 * 42 = –6174

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Question

If z + 2x = 10 and 7z + 2x = 16, what is z?

Answer

Subtract the first expression from the second. That gives you 6z = 6. That simplifies to z = 1.

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Question

If the function g is defined by g(x) = 4_x_ + 5, then 2_g_(x) – 3 =

Answer

The function g(x) is equal to 4_x_ + 5, and the notation 2_g_(x) asks us to multiply the entire function by 2. 2(4_x_ + 5) = 8_x_ + 10. We then subtract 3, the second part of the new equation, to get 8_x_ + 7.

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Question

If f(x) = x_2 + 5_x and g(x) = 2, what is f(g(4))?

Answer

First you must find what g(4) is. The definition of g(x) tells you that the function is always equal to 2, regardless of what “x” is. Plugging 2 into f(x), we get 22 + 5(2) = 14.

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Question

f(a) = 1/3(a_3 + 5_a – 15)

Find a = 3.

Answer

Substitute 3 for all a.

(1/3) * (33 + 5(3) – 15)

(1/3) * (27 + 15 – 15)

(1/3) * (27) = 9

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Question

Evaluate f(g(6)) given that f(x) = _x_2 – 6 and g(x) = –(1/2)x – 5

Answer

Begin by solving g(6) first.

g(6) = –(1/2)(6) – 5

g(6) = –3 – 5

g(6) = –8

We substitute f(–8)

f(–8) = (–8)2 – 6

f(–8) = 64 – 6

f(–8) = 58

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Question

If f(x) = |(_x_2 – 175)|, what is the value of f(–10) ?

Answer

If x = –10, then (_x_2 – 175) = 100 – 175 = –75. But the sign |x| means the absolute value of x. Absolute values are always positive.

|–75| = 75

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Question

If f(x)= 2x² + 5x – 3, then what is f(–2)?

Answer

By plugging in –2 for x and evaluating, the answer becomes 8 – 10 – 3 = -5.

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Question

If f(x) = x² – 2 and g(x) = 3x + 5, what is f(g(x))?

Answer

To find f(g(x) plug the equation for g(x) into equation f(x) in place of “x” so that you have: f(g(x)) = (3x + 5)² – 2.

Simplify: (3x + 5)(3x + 5) – 2

Use FOIL: 9x² + 30x + 25 – 2 = 9x² + 30x + 23

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Question

If f(x)=3x and g(x)=2x+2, what is the value of f(g(x)) when x=3?

Answer

With composition of functions (as with the order of operations) we perform what is inside of the parentheses first. So, g(3)=2(3)+2=8 and then f(8)=24.

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Question

The cost of a cell phone plan is $40 for the first 100 minutes of calls, and then 5 cents for each minute after. If the variable x is equal to the number of minutes used for calls in a month on that cell phone plan, what is the equation f(x) for the cost, in dollars, of the cell phone plan for calls during that month?

Answer

40 dollars is the constant cost of the cell phone plan, regardless of minute usage for calls. We then add 5 cents, or 0.05 dollars, for every minute of calls over 100. Thus, we do not multiply 0.05 by x, but rather by (x - 100), since the 5 cent charge only applies to minutes used that are over the 100-minute barrier. For example, if you used 101 minutes for calls during the month, you would only pay the 5 cents for that 101st minute, making your cost for calls $40.05. Thus, the answer is 40 + 0.05(x - 100).

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Question

f(x) = 4x + 2

g(x) = 3x - 1

The two equations above define the functions f(x) = g(x). If f(d) = 2g(d) for some value of d, then what is the value of d?

Answer

f(x) = 4x + 2

g(x) = 3x - 1

We have f(d) = 2g(d). We multiply each value in g(d) by 2.

4d + 2 = 2(3d - 1) (Distribute the 2 in the parentheses by multiplying each value in them by 2.)

4d + 2 = 6d - 2 (Add 2 to both sides.)

4d + 4 = 6d (Subtract 4d from both sides.)

4 = 2d (Divide both sides by 2.)

2 = d

We can plug that back in to double check.

4(2) + 2 = 6(2) - 2

8 + 2 = 12 - 2

10 = 10

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Question

The function f, where f(x) = x2 + 6x + 8, is related to function g, where g(x) = 5 f(x-2). What is g(3)?

Answer

Doing things in an orderly way is a friend to the test-taker.

g(3) = 5 f(3-2)

= 5 f(1)

= 5 \[ 12 + 6**∙**1 + 8\]

= 5 \[ 1 + 6 + 8\]

= 5 \[ 15\]

= 75

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Question

A function F is defined as follows:

for x2 > 1, F(x) = 4x2 + 2x – 2

for x2 < 1, F(x) = 4x2 – 2x + 2

What is the value of F(1/2)?

Answer

For F(1/2), x2=1/4, which is less than 1, so we use the bottom equation to solve. This gives F(1/2)= 4(1/2)2 – 2(1/2) + 2 = 1 – 1 + 2 = 2

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Question

If f(x) = _x_2 – 5 for all values x and f(a) = 4, what is one possible value of a?

Answer

Using the defined function, f(a) will produce the same result when substituted for x:

f(a) = _a_2 – 5

Setting this equal to 4, you can solve for a:

_a_2 – 5 = 4

_a_2 = 9

a = –3 or 3

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Question

The function is defined as . What is ?

Answer

Substitute -1 for in the given function.

If you didn’t remember the negative sign, you will have calculated 36. If you remembered the negative sign at the very last step, you will have calculated -36; however, if you did not remember that is 1, then you will have calculated 18.

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Question

f(x) = 2x2 + x – 3 and g(y) = 2y – 7. What is f(g(4))?

Answer

To evaluate f(g(4)), one must first determine the value of g(4), then plug that into f(x).

g(4) = 2 x 4 – 7 = 1.

f(1) = 2 x 12 + 2 x 1 – 3 = 0.

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Question

What is the value of the function f(x) = 6x2 + 16x – 6 when x = –3?

Answer

There are two ways to do this problem. The first way just involves plugging in –3 for x and solving 6〖(–3)〗2 + 16(–3) – 6, which equals 54 – 48 – 6 = 0. The second way involves factoring the polynomial to (6x – 2)(x + 3) and then plugging in –3 for x. The second way quickly shows that the answer is 0 due to multiplying by (–3 + 3).

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