Card 0 of 20
Solve the equation for x and y.
x² + y = 31
x + y = 11
Solving the equation follows the same system as the first problem. However since x is squared in this problem we will have two possible solutions for each unknown. Again substitute y=11-x and solve from there. Hence, x2+11-x=31. So x2-x=20. 5 squared is 25, minus 5 is 20. Now we know 5 is one of our solutions. Then we must solve for the second solution which is -4. -4 squared is 16 and 16 –(-4) is 20. The last step is to solve for y for the two possible solutions of x. We get 15 and 6. The graph below illustrates to solutions.
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Solve the equation for x and y.
x² – y = 96
x + y = 14
This problem is very similar to number 2. Derive y=14-x and solve from there. The graph below illustrates the solution.
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Solve the equation for x and y.
5_x_² + y = 20
x_² + 2_y = 10
The problem involves the same method used for the rest of the practice set. However since the x is squared we will have multiple solutions. Solve this one in the same way as number 2. However be careful to notice that the y value is the same for both x values. The graph below illustrates the solution.
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Solve the equation for x and y.
_x_² + y = 60
x – y = 50
This is a system of equations problem with an x squared, to be solved just like the rest of the problem set. Two solutions are required due to the x2. The graph below illustrates those solutions.
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A line passes through the points and
. What is the equation for the line?
First we will calculate the slope as follows:
And our equation for a line is
Now we need to calculate b. We can pick either of the points given and solve for
Our equation for the line becomes
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Which of the following lines does not intersect the line ?
Parallel lines never intersect, so you are looking for a line that has the same slope as the one given. The slope of the given line is –4, and the slope of the line in y = –4_x_ + 5 is –4 as well. Since these two lines have equal slopes, they will run parallel and can never intersect.
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If the equation of a line is 4_y_ – x = 48, at what point does that line cross the x-axis?
When the equation crosses the x-axis, y = 0. Plug 0 into the equation for y, and solve for x.
4(0) – x = 48, –x = 48, x = –48
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Where does the graph of 2x + 3y = 15 cross the x-axis?
To find the x-intercept, set y=0 and solve for x. This gives an answer of x = 7.5.
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The slope of a line is equal to -3/4. If that line intersects the y-axis at (0,15), at what point does it intersect the x-axis?
If the slope of the line m=-3/4, when y=15 and x=0, plug everything into the equation y=mx+b.
Solving for b:
15=(-3/4)*0 + b
b=15
y=-3/4x + 15
To get the x-axis intersect, plug in y=0 and solve for x.
0 = -3/4x + 15
3/4x = 15
3x = 15*4
x = 60/3 = 20
x=20
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Find the y-intercept of .
To find the y-intercept, set x equal to zero and solve for y.
This gives y = 3(0)2 + 2(0) +7 = 7.
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If these three points are on a single line, what is the formula for the line?
(3,3)
(4,7)
(5,11)
Formula for a line: y = mx + b
First find slope from two of the points: (3,3) and (4,7)
m = slope = (y2 – y1) / x2 – x1) = (7-3) / (4-3) = 4 / 1 = 4
Solve for b by plugging m and one set of coordinates into the formula for a line:
y = mx + b
11 = 4 * 5 + b
11 = 20 + b
b = -9
y = 4x - 9
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The slope of a line is 5/8 and the x-intercept is 16. Which of these points is on the line?
y = mx + b
x intercept is 16 therefore one coordinate is (16,0)
0 = 5/8 * 16 + b
0 = 10 + b
b = -10
y = 5/8 x – 10
if x = 32
y = 5/8 * 32 – 10 = 20 – 10 = 10
Therefore (32,10)
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A line has the equation: x+y=1.
What is the y-intercept?
x+y=1 can be rearranged into: y=-x+1. Using the point-slope form, we can see that the y-intercept is 1.
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A line has the equation: 2x+4y=8.
What is the x-intercept?
To find the x-intercept, rearrange the equation 2x+4y=8 so that x is isolated:
2x=-4y+8
x=-2y+4
Using the point-slope formula, we see that the x-intercept is 4.
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Given the line , what is the sum of the
-intercept and the
-intercept?
Intercepts occur when a line crosses the -axis or the
-axis. When the line crosses the
-axis, then
and
. When the line crosses the
-axis, then
and
. The intercept points are
and
. So the
-intercept is
and the
intercept is
and the sum is
.
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What is the y intercept of the following function of x?
y = 3x
The answer is 0 because in slope intercept form, y = mx + b; b is the y intercept. In this case b = 0.
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What is the x-intercept of a line with a slope of 5 and y-intercept of 3.5?
To solve this, first find the equation of our line. The form of the question gives it to us very directly. We can use the slope-intercept form (y = mx + b).
y = 5x + 3.5
The x-intercept is found by setting y = 0, because that will give us the x-value at which the line crosses the x-axis.
0 = 5x + 3.5; –3.5 = 5x; x = –3.5 / 5 or –0.7. The point will be (–0.7, 0)
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Determine the y-intercept of the following line:
The y-intercept occurs when
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At what point does the graph cross the
-axis?
The graph crosses the -axis where
. So plugging in and solving yields
.
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Find the x-intercepts of .
To find the x-intercepts, plug into the equation and solve for
.
Don't forget that there are two solutions, both negative and positive!
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