Card 0 of 20
Given the equation above, what is the value of ?
Use FOIL to expand the left side of the equation.
From this equation, we can solve for ,
, and
.
Plug these values into to solve.
Compare your answer with the correct one above
Which of the following is equal to the expression ?
Multiply using FOIL:
First = 3x(2x) = 6x2
Outter = 3x(4) = 12x
Inner = -1(2x) = -2x
Last = -1(4) = -4
Combine and simplify:
6x2 + 12x - 2x - 4 = 6x2 +10x - 4
Compare your answer with the correct one above
If , what is the value of
?
Remember that (a – b )(a + b ) = a 2 – b 2.
We can therefore rewrite (3_x –_ 4)(3_x_ + 4) = 2 as (3_x_ )2 – (4)2 = 2.
Simplify to find 9_x_2 – 16 = 2.
Adding 16 to each side gives us 9_x_2 = 18.
Compare your answer with the correct one above
If and
, then which of the following is equivalent to
?
We are asked to find the difference between g(h(x)) and h(g(x)), where g(x) = 2x2 – 2 and h(x) = x + 4. Let's find expressions for both.
g(h(x)) = g(x + 4) = 2(x + 4)2 – 2
g(h(x)) = 2(x + 4)(x + 4) – 2
In order to find (x+4)(x+4) we can use the FOIL method.
(x + 4)(x + 4) = x2 + 4x + 4x + 16
g(h(x)) = 2(x2 + 4x + 4x + 16) – 2
g(h(x)) = 2(x2 + 8x + 16) – 2
Distribute and simplify.
g(h(x)) = 2x2 + 16x + 32 – 2
g(h(x)) = 2x2 + 16x + 30
Now, we need to find h(g(x)).
h(g(x)) = h(2x2 – 2) = 2x2 – 2 + 4
h(g(x)) = 2x2 + 2
Finally, we can find g(h(x)) – h(g(x)).
g(h(x)) – h(g(x)) = 2x2 + 16x + 30 – (2x2 + 2)
= 2x2 + 16x + 30 – 2x2 – 2
= 16x + 28
The answer is 16x + 28.
Compare your answer with the correct one above
Simplify the expression.
Solve by applying FOIL:
First: 2x2 * 2y = 4x2y
Outer: 2x2 * a = 2ax2
Inner: –3x * 2y = –6xy
Last: –3x * a = –3ax
Add them together: 4x2y + 2ax2 – 6xy – 3ax
There are no common terms, so we are done.
Compare your answer with the correct one above
The sum of two numbers is . The product of the same two numbers is
. If the two numbers are each increased by one, the new product is
. Find
in terms of __
_.
Let the two numbers be x and y.
x + y = s
xy = p
(x + 1)(y + 1) = q
Expand the last equation:
xy + x + y + 1 = q
Note that both of the first two equations can be substituted into this new equation:
p + s + 1 = q
Solve this equation for q – p by subtracting p from both sides:
s + 1 = q – p
Compare your answer with the correct one above
Expand the expression:
When using FOIL, multiply the first, outside, inside, then last expressions; then combine like terms.
Compare your answer with the correct one above
Expand the following expression:
Which becomes
Or, written better
Compare your answer with the correct one above
Compare your answer with the correct one above
Expand and simplify the expression.
We can solve by FOIL, then distribute the . Since all terms are being multiplied, you will get the same answer if you distribute the
before using FOIL.
First:
Inside:
Outside:
Last:
Sum all of the terms and simplify. Do not forget the in front of the quadratic!
Finally, distribute the .
Compare your answer with the correct one above
Expand and simplify:
Use the FOIL method in the distributive property to simplify the expression:
First simplify the radicals,
Compare your answer with the correct one above
If , what is the value of
?
Use the FOIL method to distribute terms and simplify the equation:
Compare your answer with the correct one above
Expand the expression .
Use the FOIL method (first, outer, inner, last) to multiply expressions and combine like terms:
Compare your answer with the correct one above
Simplify:
Use the FOIL method to simplify. Use the following formula to simplify.
Substitute and follow the terms.
Combine like terms.
The answer is :
Compare your answer with the correct one above
Simplify:
Use the FOIL method to solve. Follow the example below:
Simplify the expression.
The answer is:
Compare your answer with the correct one above
Which of the following expressions is equivalent to ?
Using the FOIL method for multiplying binomial expressions:
Compare your answer with the correct one above
Expand the following expression found below:
If a problem asks you to expand an expression, you must use the Distributive property. If you are using the FOIL method, you first multiply the first term in each parentheses by each other, followed by the outside terms, then the inside terms, and then the last terms. This is illustrated below.
First, you multiply which equals
Second, you multiply
Third, you multiply
Last, you multiply
Then you simply rearrange them in order of exponents to get
Compare your answer with the correct one above
Use FOIL to multiply the expressions:
The term FOIL stands for First, Outside, Inside, Last. It refers to the order in which you distribute between the two expressions, which allows each monomial to multiplied by each monomial in the neighboring expression. For this problem that would look like this:
Compare your answer with the correct one above
Use FOIL to multiply the expressions:
The term FOIL stands for First, Outside, Inside, Last. It refers to the order in which you distribute between the two expressions, which allows each monomial to multiplied by each monomial in the neighboring expression. For this problem that would look like this:
Compare your answer with the correct one above
Use FOIL to multiply the expressions:
The term FOIL stands for First, Outside, Inside, Last. It refers to the order in which you distribute between the two expressions, which allows each monomial to multiplied by each monomial in the neighboring expression. For this problem that would look like this:
Compare your answer with the correct one above