Range and Domain - SAT Subject Test in Math I

Card 0 of 20

Question

Find the domain:

Answer

To find the domain, find all areas of the number line where the fraction is defined.

because the denominator of a fraction must be nonzero.

Factor by finding two numbers that sum to -2 and multiply to 1. These numbers are -1 and -1.

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Question

is a sine curve. What are the domain and range of this function?

Question_2

Answer

The domain includes the values that go into a function (the x-values) and the range are the values that come out (the or y-values). A sine curve represent a wave the repeats at a regular frequency. Based upon this graph, the maximum is equal to 1, while the minimum is equal to –1. The x-values span all real numbers, as there is no limit to the input fo a sine function. The domain of the function is all real numbers and the range is .

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Question

Give the domain of the function below.

Answer

The domain is the set of possible value for the variable. We can find the impossible values of by setting the denominator of the fractional function equal to zero, as this would yield an impossible equation.

Now we can solve for .

There is no real value of that will fit this equation; any real value squared will be a positive number.

The radicand is always positive, and is defined for all real values of . This makes the domain of the set of all real numbers.

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Question

If , which of these values of is NOT in the domain of this equation?

Answer

Using as the input () value for this equation generates an output () value that contradicts the stated condition of .

Therefore is not a valid value for and not in the equation's domain:

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Question

Which of the following is NOT a function?

Answer

A function has to pass the vertical line test, which means that a vertical line can only cross the function one time. To put it another way, for any given value of , there can only be one value of . For the function , there is one value for two possible values. For instance, if , then . But if , as well. This function fails the vertical line test. The other functions listed are a line,, the top half of a right facing parabola, , a cubic equation, , and a semicircle, . These will all pass the vertical line test.

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Question

What is the range of the function?

Answer

This function is a parabola that has been shifted up five units. The standard parabola has a range that goes from 0 (inclusive) to positive infinity. If the vertex has been moved up by 5, this means that its minimum has been shifted up by five. The first term is inclusive, which means you need a "\[" for the beginning.

Minimum: 5 inclusive, maximum: infinity

Range:

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Question

What is the domain of the function?

Answer

The domain represents the acceptable values for this function. Based on the members of the function, the only limit that you have is the non-allowance of a negative number (because of the square root). The square and the linear terms are fine with any numbers. You cannot have any negative values, otherwise the square root will not be a real number.

Minimum: 0 inclusive, maximum: infinity

Domain:

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Question

What is the domain of the function?

Answer

There are two limitations in the function: the radical and the denominator term. A radical cannot have a negative term, and a denominator cannot be equal to zero. Based on the first restriction (the radical), our term must be greater than or equal to zero. Based on the second restriction (the denominator), our term cannot be equal to 4. Our final answer will be the union of these two sets.

Minimum: 0 (inclusive), maximum: infinity

Exclusion: 4

Domain:

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Question

What is the domain of the function?

Answer

The domain of a function refers to the viable value inputs. Common domain restrictions involve radicals (which cannot be negative) and fractions (which cannot have a zero denominator).

This function does not have any such restrictions; any value of will result in a real number. The domain is thus unlimited, ranging from negative infinity to infinity.

Domain:

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Question

What is the range of the function?

Answer

This function represents a parabola that has been shifted 15 units to the left and 2 units up from its standard position.

The vertex of a standard parabola is at (0,0). By shifting the graph as described, the new vertex is at (-15,2). The value of the vertex represents the minimum of the range; since the parabola opens upward, the maximum will be infinity. Note that the range is inclusive of 2, so you must use a bracket "\[".

Minimum: 2 (inclusive), maximum: infinity

Range:

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Question

What is the domain of the function?

Answer

The domain of a function refers to the viable value inputs. Common domain restrictions involve radicals (which cannot be negative) and fractions (which cannot have a zero denominator). Both of these restrictions can be found in the given function.

Let's start with the radical, which must be greater than or equal to zero:

Next, we will look at the fraction denominator, which cannot equal zero:

Our final answer will be the union of the two sets.

Minimum: 2 (inclusive), maximum: infinity

Exclusion: 22

Domain:

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Question

Find the range of the function for the domain .

Answer

The range of a function is the group of corresponding values for a given domain ( values). Plug each value into the function to find the range:

The range is .

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Question

Define .

Give the domain of .

Answer

The radicand within a square root symbol must be nonnegative, so

This happens if and only if , so the domain of is .

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Question

What is the domain of the following function? Please use interval notation.

Answer

A basic knowledge of absolute value and its functions is valuable for this problem. However, if you do not know what the typical shape of an absoluate value function looks like, one can always plug in values and plot points.

Upon doing so, we learn that the -values (domain) are not restricted on either end of the function, creating a domain of negative infinity to postive infinity.

If we plug in -100000 for , we get 100000 for .

If we plug in 100000 for , we get 100000 for .

Additionally, if we plug in any value for , we will see that we always get a real, defined value for .

**Extra Note: Due to the absolute value notation, the negative (-) next to the is not important, in that it will always be made positive by the absolute value, making this function the same as . If the negative (-) was outside of the absolute value, this would flip the function, making all corresponding -values negative. However, this knowledge is most important for range, rather than domain.

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Question

What is the range of the following function? Please use interval notation.

Answer

A basic knowledge of absolute value and its functions is valuable for this problem. However, if you do not know what the typical shape of an absoluate value function looks like, one can always plug in values and plot points.

Upon doing so, we learn that the -values (range) never surpass . This is because of the negative that is placed outside of the absolute value function. Meaning, for every value we plug in, we will always get a negative value for , except when .

With this knowledge, we can now confidently state the range as

**Extra note: the negative sign outside of the absolute value is simply a transformation of , reflecting the function about the -axis.

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Question

Define .

Give the range of .

Answer

The radicand within a square root symbol must be nonnegative, so

This happens if and only if , so the domain of is .

assumes its greatest value when , which is the point on where is least - this is at .

Similarly, assumes its least value when , which is the point on where is greatest - this is at .

Therefore, the range of is .

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Question

Use the following function and domain to answer this question

Find the range of the function for the given doman. Are and directly or inversely related?

Answer

To find the range, plug each value of the domain into the equation:

As the x-values increase, the y-values do as well. Therefore there is a relationship

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Question

A function has the following range:

Which of the following CANNOT be the domain of the function.

Answer

Functions cannot have more than one value for each value. This means different numbers in the range cannot be assigned to the same value in the domain. Therefore, cannot be the domain of the function.

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Question

Define the functions and on the set of real numbers as follows:

Give the natural domain of the composite function .

Answer

The natural domain of the composite function is defined to be the intersection two sets.

One set is the natural domain of . Since is a polynomial, its domain is the set of all real numbers.

The other set is the set of all values of such that that is in the domain of . Since the radicand of the square root in must be nonnegative,

, and , the domain of

Therefore, the other set is the set of all such that

Substitute:

This holds for all real numbers, so this set is also the set of all real numbers.

The natural domain of is the set of all real numbers.

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Question

Find the domain and range of the function . Express the domain and range in interval notation.

Answer

Finding the Domain

The domain of a function is defined as the set of all valid input values of overwhich the function is defined. The simple rule of thumb for rational functions is that all real numbers will work except for those in which denominator is zero since division by zero is not allowed.

Set the denominator to zero and solve for ,

The function is therefore defined everywhere except at . Therefore the domain expressed in interval notation is,

Note that the open parentheses indicate that is not in the domain, but may become arbitrarily close to .

Finding the Range

The range of a function is defined as the set of all outputs spanning the domain. Finding the range can be achieved by finding the domain of the inverse function. First solve for to obtain the inverse function,

Multiply both sides by ,

Distribute ,

Move all terms with to one side of the equation,

Factor and solve for

The inverse function is therefore,

Find the domain of the inverse function,

The range of is the domain of , which is:

If you look at the plots for the function (in blue) and (in red and labeled as in the figure) you can see the asymptotic behavior of as approaches and of as approaches .

Problem 1 plot2

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