Stoichiometry with Reactions - SAT Subject Test in Chemistry
Card 0 of 2
Octane, 
, is an important of component of gasoline, which can be burned as fuel in cars. The following is an unbalanced equation for the combustion of octane.
If 114 g of octane are burned in the complete combustion reaction shown below, how many grams of water will be produced?
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Octane,
If 114 g of octane are burned in the complete combustion reaction shown below, how many grams of water will be produced?
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First, the equation should be balanced. This can be done with the coefficients 2, 25, 16, and 18.
Next, calculating the molar mass of octane shows that it has a molar mass of 114 g/mol. This means that 1 mole of octane is used in the reaction, and 9 times as many moles of water should be produced, meaning one of the products will be 9 mol of water. Water has a molar mass of 18 g/mol, so the total mass of water produced is 
.
First, the equation should be balanced. This can be done with the coefficients 2, 25, 16, and 18.
Next, calculating the molar mass of octane shows that it has a molar mass of 114 g/mol. This means that 1 mole of octane is used in the reaction, and 9 times as many moles of water should be produced, meaning one of the products will be 9 mol of water. Water has a molar mass of 18 g/mol, so the total mass of water produced is
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Suppose that 4 moles of 
undergoes complete decomposition. At STP, how many liters of 
would be produced as product? (At STP, one mole of a gas takes up 22.4 L of space.)
Suppose that 4 moles of
Start by creating a skeleton equation for the decomposition reaction:
This can be balanced to give:
This means that 4 mol of reactant would produce 6 mol of oxygen gas. The question states that at STP, one mole of a gas takes up 22.4 L of space, so it is easy to find that 6 moles of oxygen gas would occupy a volume of 134.4 L:
Start by creating a skeleton equation for the decomposition reaction:
This can be balanced to give:
This means that 4 mol of reactant would produce 6 mol of oxygen gas. The question states that at STP, one mole of a gas takes up 22.4 L of space, so it is easy to find that 6 moles of oxygen gas would occupy a volume of 134.4 L:
Compare your answer with the correct one above