Card 0 of 11
Given the equation above, what is the value of ?
Use FOIL to expand the left side of the equation.
From this equation, we can solve for ,
, and
.
Plug these values into to solve.
Compare your answer with the correct one above
Which of the following is equal to the expression ?
Multiply using FOIL:
First = 3x(2x) = 6x2
Outter = 3x(4) = 12x
Inner = -1(2x) = -2x
Last = -1(4) = -4
Combine and simplify:
6x2 + 12x - 2x - 4 = 6x2 +10x - 4
Compare your answer with the correct one above
If , what is the value of
?
Remember that (a – b )(a + b ) = a 2 – b 2.
We can therefore rewrite (3_x –_ 4)(3_x_ + 4) = 2 as (3_x_ )2 – (4)2 = 2.
Simplify to find 9_x_2 – 16 = 2.
Adding 16 to each side gives us 9_x_2 = 18.
Compare your answer with the correct one above
If and
, then which of the following is equivalent to
?
We are asked to find the difference between g(h(x)) and h(g(x)), where g(x) = 2x2 – 2 and h(x) = x + 4. Let's find expressions for both.
g(h(x)) = g(x + 4) = 2(x + 4)2 – 2
g(h(x)) = 2(x + 4)(x + 4) – 2
In order to find (x+4)(x+4) we can use the FOIL method.
(x + 4)(x + 4) = x2 + 4x + 4x + 16
g(h(x)) = 2(x2 + 4x + 4x + 16) – 2
g(h(x)) = 2(x2 + 8x + 16) – 2
Distribute and simplify.
g(h(x)) = 2x2 + 16x + 32 – 2
g(h(x)) = 2x2 + 16x + 30
Now, we need to find h(g(x)).
h(g(x)) = h(2x2 – 2) = 2x2 – 2 + 4
h(g(x)) = 2x2 + 2
Finally, we can find g(h(x)) – h(g(x)).
g(h(x)) – h(g(x)) = 2x2 + 16x + 30 – (2x2 + 2)
= 2x2 + 16x + 30 – 2x2 – 2
= 16x + 28
The answer is 16x + 28.
Compare your answer with the correct one above
Simplify the expression.
Solve by applying FOIL:
First: 2x2 * 2y = 4x2y
Outer: 2x2 * a = 2ax2
Inner: –3x * 2y = –6xy
Last: –3x * a = –3ax
Add them together: 4x2y + 2ax2 – 6xy – 3ax
There are no common terms, so we are done.
Compare your answer with the correct one above
The sum of two numbers is . The product of the same two numbers is
. If the two numbers are each increased by one, the new product is
. Find
in terms of __
_.
Let the two numbers be x and y.
x + y = s
xy = p
(x + 1)(y + 1) = q
Expand the last equation:
xy + x + y + 1 = q
Note that both of the first two equations can be substituted into this new equation:
p + s + 1 = q
Solve this equation for q – p by subtracting p from both sides:
s + 1 = q – p
Compare your answer with the correct one above
Expand the expression:
When using FOIL, multiply the first, outside, inside, then last expressions; then combine like terms.
Compare your answer with the correct one above
Expand the following expression:
Which becomes
Or, written better
Compare your answer with the correct one above
Compare your answer with the correct one above
Expand and simplify the expression.
We can solve by FOIL, then distribute the . Since all terms are being multiplied, you will get the same answer if you distribute the
before using FOIL.
First:
Inside:
Outside:
Last:
Sum all of the terms and simplify. Do not forget the in front of the quadratic!
Finally, distribute the .
Compare your answer with the correct one above
If ,
, and
, then
To find what equals, you must know how to multiply
times
, or, you must know how to multiply binomials. The best way to multiply monomials is the FOIL (first, outside, inside, last) method, as shown below:
Multiply the First terms
Multiply the Outside terms:
Multiply the Inside terms:
Note: this step yields a negative number because the product of the two terms is negative.
Multiply the Last terms:
Note: this step yields a negative number too!
Putting the results together, you get:
Finally, combine like terms, and you get:
Compare your answer with the correct one above