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Jesse has a large movie collection containing X movies. 1/3 of his movies are action movies, 3/5 of the remainder are comedies, and the rest are historical movies. How many historical movies does Jesse own?
1/3 of the movies are action movies. 3/5 of 2/3 of the movies are comedies, or (3/5)*(2/3), or 6/15. Combining the comedies and the action movies (1/3 or 5/15), we get 11/15 of the movies being either action or comedy. Thus, 4/15 of the movies remain and all of them have to be historical.
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If x = 1/3 and y = 1/2, find the value of 2_x_ + 3_y_.
Substitute the values of x and y into the given expression:
2(1/3) + 3(1/2)
= 2/3 + 3/2
= 4/6 + 9/6
= 13/6
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Solve .
Finding the common denominator yields . We can then evaluate leaving
.
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What is the solution, reduced to its simplest form, for ?
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What is the sum of and
?
We can begin by eliminating the obviously wrong answers. We know that the sum of the two fractions will be more than 1, so the answer choices and
are out. Now, let's add the two fractions:
Begin by converting to
.
Now find the common denominator of and
. The least common multiple of 5 and 6 is 30, so 30 is the common denominator. Now alter both fractions so that they use the common denominator:
Now we can easily add the two fractions together:
The answer is .
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Simplify:
Division is the same as multiplying by the reciprocal. Thus, a/b ÷ c/d = a/b x d/c = ad/bc
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If p is a positive integer, and 4 is the remainder when p-8 is divided by 5, which of the following could be the value of p?
Remember that if x has a remainder of 4 when divided by 5, xminus 4 must be divisible by 5. We are therefore looking for a number p such that p - 8 - 4 is divisible by 5. The only answer choice that fits this description is 17.
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If and
, then what is the value of
?
Dividing by a number (in this case ) is equivalent to multiplying by its reciprocal (in this case
). Therefore:
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Evaluate the following:
First we will evaluate the terms in the parentheses:
Next, we will square the first fraction:
We can evaluate the division as such:
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Simplify:
Start by rewriting this fraction as a division problem:
When dividing fractions, you multiply by the reciprocal of the second fraction, so you can rewrite your problem like this:
Multiply across the numerators and then across the denominators to get . The x's cancel, and you can reduce the fraction to be
.
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Define an operation as follows:
For all real numbers ,
.
Evaluate .
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Define an operation as follows:
For all real numbers ,
.
Evaluate .
,
or, equivalently,
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Define an operation as follows:
For all real numbers ,
.
Evaluate .
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Define an operation as follows:
For all real numbers ,
.
Evaluate .
, or, equivalently,
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Define an operation as follows:
For all real numbers ,
.
Evaluate .
,
or, equivalently,
From here we need to find a common denominator.
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Define an operation as follows:
For all real numbers ,
.
Evaluate .
or, equivalently,
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Simplify:
Begin by simplifying any additions that need to be done:
becomes
Now, remember that the numerator can be rewritten
:
Now, when you divide fractions, you multiply the numerator by the reciprocal of the denominator:
Cancel the s and you get:
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If xy = 1 and 0 < x < 1, then which of the following must be true?
If x is between 0 and 1, it must be a proper fraction (e.g., ½ or ¼). Solving the first equation for y, y = 1/x. When you divide 1 by a proper fraction between 0 and 1, the result is the reciprocal of that fraction, which will always be greater than 1.
To test this out, pick any fraction. Say x = ½. This makes y = 2.
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Before going to school, Joey ran 1/3 of his daily total miles. In gym class, Joey did 2/3 of the remainder. What part of his daily total miles was left for after school?
Before school, Joey did 1/3 of the total miles. In school, Joey did 2/3 of the remaining 2/3, or 4/9 of the running. When added to his in school run, his before school run of 3/9 brings his completed miles to 7/9 of his dialy total. Thus, only 2/9 of the total miles are left for after school.
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