Symmetry - Pre-Calculus

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Question

Is the following function symmetric across the y-axis? (Is it an even function?)

Answer

One way to determine algebraically if a function is an even function, or symmetric about the y-axis, is to substitute in for . When we do this, if the function is equivalent to the original, then the function is an even function. If not, it is not an even function.

For our function:

Thus the function is not symmetric about the y-axis.

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Question

Is the following function symmetric across the y-axis? (Is it an even function?)

Answer

One way to determine algebraically if a function is an even function, or symmetric about the y-axis, is to substitute in for . When we do this, if the function is equivalent to the original, then the function is an even function. If not, it is not an even function.

For our function:

Since this matches the original, our function is symmetric across the y-axis.

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Question

Determine if there is symmetry with the equation to the -axis and the method used to determine the answer.

Answer

In order to determine if there is symmetry about the x-axis, replace all variables with . Solving for , if the new equation is the same as the original equation, then there is symmetry with the x-axis.

Since the original and new equations are not equivalent, there is no symmetry with the x-axis.

The correct answer is:

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Question

Is the following function symmetrical about the y axis (is it an even function)?

Answer

For a function to be even, it must satisfy the equality

Likewise if a function is even, it is symmetrical about the y-axis

Therefore, the function is not even, and so the answer is No

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Question

Algebraically check for symmetry with respect to the x-axis, y axis, and the origin.

Answer

For a function to be symmetrical about the y-axis, it must satisfy so there is not symmetry about the y-axis

For a function to be symmetrical about the x-axis, it must satisfy so there is symmetry about the x-axis

For a function to be symmetrical about the origin, you must replace y with (-y) and x with (-x) and the resulting function must be equal to the original function.

-So there is no symmetry about the origin, and the answer is Symmetrical about the x-axis

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Question

Algebraically check for symmetry with respect to the x-axis, y axis, and the origin.

Answer

For a function to be symmetrical about the y-axis, it must satisfy so there is symmetry about the y-axis

For a function to be symmetrical about the x-axis, it must satisfy

so there is not symmetry about the x-axis

For a function to be symmetrical about the origin, you must replace y with (-y) and x with (-x) and the resulting function must be equal to the original function.

So there is no symmetry about the origin.

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Question

Is the following function symmetrical about the y-axis (is it an even function)?

Answer

For a function to be even, it must satisfy the equality

Likewise, if a function is even, it is symmetrical about the y-axis

Therefore, the function is not even, and so the answer is No.

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Question

Which of the following best describes the symmetry of with respect to the x-axis, y-axis, and the origin.

Answer

For a function to be symmetrical about the y-axis, it must satisfy

so there is not symmetry about the y-axis

For a function to be symmetrical about the x-axis, it must satisfy

so there is symmetry about the x-axis

For a function to be symmetrical about the origin, you must replace y with (-y) and x with (-x), and the resulting function must be equal to the original function.

So there is no symmetry about the origin, and the answer is Symmetrical about the x-axis.

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Question

Algebraically check for symmetry with respect to the x-axis, y-axis, and the origin.

Answer

For a function to be symmetrical about the y-axis, it must satisfy

so there is symmetry about the y-axis

For a function to be symmetrical about the x-axis, it must satisfy

so there is not symmetry about the x-axis

For a function to be symmetrical about the origin, you must replace y with (-y) and x with (-x) and the resulting function must be equal to the original function.

So there is no symmetry about the origin, and the credited answer is "symmetry about the y-axis".

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