Evaluate geometric vectors - Pre-Calculus

Card 0 of 20

Question

Express a vector with magnitude 2.24 directed 63.4° CCW from the x-axis in unit vector form.

Answer

The x-coordinate is the magnitude times the cosine of the angle, while the y-coordinate is the magnitude times the sine of the angle.

Q01_01

The resultant vector is: .

Compare your answer with the correct one above

Question

What is the magnitude and angle for the following vector, measured CCW from the x-axis?

Answer

The magnitude of the vector is found using the distance formula:

Vq02_02

To calculate the angle we must first find the inverse tangent of :

This angle value is the principal arctan, but it is in the fourth quadrant while our vector is in the second. We must add the angle 180° to this value to arrive at our final answer.

Compare your answer with the correct one above

Question

Vector has a magnitude of 3.61 and a direction 124° CCW from the x-axis. Express in unit vector form.

Answer

For vector , the magnitude is doubled, but the direction remains the same.

Vq03_01

For our calculation, we use a magnitude of:

The x-coordinate is the magnitude times the cosine of the angle, while the y-coordinate is the magnitude times the sine of the angle.

The resultant vector is: .

Vq03_02

Compare your answer with the correct one above

Question

What are the magnitude and angle, CCW from the x-axis, of ?

Answer

When multiplying a vector by a constant (called scalar multiplication), we multiply each component by the constant.

Vq04_01

The magnitude of this new vector is found with these new components:

Vq04_02

To calculate the angle we must first find the inverse tangent of :

This is the principal arctan, but it is in the first quadrant while our vector is in the third. We to add the angle 180° to this value to arrive at our final answer.

Compare your answer with the correct one above

Question

Vector has a magnitude of 2.24 and is at an angle of 63.4° CCW from the x-axis. Vector has a magnitude of 3.16 at an angle of 342° CCW from the x-axis.

Find by using the nose-to-tail graphical method.

Answer

First, construct the two vectors using ruler and protractor:

Vq05_01

Place the tail of at the nose of :

Vq05_02

Construct the resultant from the tail of to the nose of :

Vq05_03

With our ruler and protractor, we find that is 4.12 at an angle of 14.0° CCW from the x-axis.

Compare your answer with the correct one above

Question

Find the magnitude and angle CCW from the x-axis of using the nose-to-tail graphical method.

Answer

Construct and from their x- and y-components:

Vq06_01

Since we are subtracting, reverse the direction of :

Vq06_02

Form by placing the tail of at the nose of :

Vq06_03

Construct and measure the resultant, , from the tail of to the nose of using a ruler and protractor:

Vq06_04

Compare your answer with the correct one above

Question

Vector has a magnitude of 2.24 and is at an angle of 63.4° CCW from the x-axis. Vector has a magnitude of 3.61 and is at an angle of 124° CCW from the x-axis.

Find by using the nose-to-tail graphical method.

Answer

First, construct the two vectors using ruler and protractor:

Vq07_01

is twice the length of , but in the same direction:

Vq07_02

Since we are subtracting, reverse the direction of :

Vq07_03

Form by placing the tail of at the nose of :

Vq07_04

Construct and measure the resultant from the tail of to the nose of with a ruler and protractor.

Vq07_05

Compare your answer with the correct one above

Question

Vector has a magnitude of 2.24 and is at an angle of 63.4° CCW from the x-axis. Vector has a magnitude of 3.16 at an anlge of 342° CCW from the x-axis.

Find by using the parallelogram graphical method.

Answer

First, construct the two vectors using ruler and protractor:

Vq08_01

Place the tails of both vectors at the same point:

Vq08_02

Construct a parallelogram:

Vq08_03

Construct and measure the resultant using ruler and protractor:

Vq08_04

Compare your answer with the correct one above

Question

Find using the parallelogram graphical method.

Answer

Construct and from their x- and y-components:

Vq09_01

Since we are subtracting, reverse the direction of :

Vq09_02

Place the tails of and at the same point:

Vq09_03

Construct a parallelogram:

Vq09_04

Construct and measure the resultant using a ruler and protractor.

Vq09_05

Compare your answer with the correct one above

Question

Vector has a magnitude of 3.61 and is at an angle of 124° CCW from the x-axis. Vector has a magnitude of 2.24 at an anlge of 63.4° CCW from the x-axis.

Find using the parallelogram graphical method.

Answer

First, construct the two vectors using ruler and protractor:

Vq10_01

is twice the length of , but in the same direction:

Vq10_02

Since we are subtracting, reverse the direction of :

Vq10_03

Place the tails of and at the same point:

Vq10_04

Construct a parallelogram:

Vq10_05

Construct and measure the resultant using ruler and protractor:

Vq10_06

Compare your answer with the correct one above

Question

Find .

Answer

Finding the resultant requires us to add like components:

Compare your answer with the correct one above

Question

Find .

Answer

Finding the resultant requires us to add like components:

Compare your answer with the correct one above

Question

Evaluate

Answer

When adding two vectors, they need to be expanded into their components. Luckily, the problem statement gives us the vectors already in their component form. From here, we just need to remember that we can only add like components. So for this problem we get:

Now we can combine those values to write out the complete vector:

Compare your answer with the correct one above

Question

Find the norm of the vector .

Answer

We find the norm of a vector by finding the sum of each element squared and then taking the square root.

.

Compare your answer with the correct one above

Question

Find the product of the vector and the scalar .

Answer

When multiplying a vector by a scalar we multiply each component of the vector by the scalar and the result is a vector:

Compare your answer with the correct one above

Question

Find the norm of the vector .

Answer

We find the norm of a vector by finding the sum of each component squared and then taking the square root of that sum.

Compare your answer with the correct one above

Question

This question refers to the previous question.

Simplify.

Answer

In order to simplify this problem we need to multiply the scalar factor to each component of the vector.

In our case the scalar factor is

Thus,

Compare your answer with the correct one above

Question

Find the norm of the vector:

Answer

The norm of a vector is also known as the length of the vector. The norm is given by the formula:

.

Here, we have

,

the correct answer.

Compare your answer with the correct one above

Question

Find the vector given by the product:

Answer

Given a scalar k and a vector v, the vector given by their products is defined component-wise:

.

Here, our product is:

Compare your answer with the correct one above

Question

Find the norm of vector .

Answer

Write the formula to find the norm, or the length the vector.

Substitute the known values of the vector and solve.

Compare your answer with the correct one above

Tap the card to reveal the answer