Using Lithium Aluminum Hydride - Organic Chemistry
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What reagents are needed to satisfy the given reaction?
What reagents are needed to satisfy the given reaction?
This problem requires that we convert our ketone group into a chlorine. However, this cannot be done directly, and requires multiple steps.
We begin by reducing the ketone with 
to form an alcoxide. The alcoxide undergoes workup (the process whereby a negatively charged oxygen gains a proton) via 
, depicted above as simply "
". We now have a secondary alcohol. From here, we can simply use the reagent 
to convert the alcohol into the desired chlorine.
This problem requires that we convert our ketone group into a chlorine. However, this cannot be done directly, and requires multiple steps.
We begin by reducing the ketone with
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Which of the following can be reduced when mixed with 
?
Which of the following can be reduced when mixed with
is a very powerful reducing agent that works to reduce almost any carbonyl compound. 
is an amide and the only carbonyl compound given of the answer choices.
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What is the product of the given reaction?
What is the product of the given reaction?
First step: esterification
Second step: lithium aluminum hydride reduction
Third step: neutralization to form primary alcohol
Fourth step: SN2 reaction to form final chlorinated product
First step: esterification
Second step: lithium aluminum hydride reduction
Third step: neutralization to form primary alcohol
Fourth step: SN2 reaction to form final chlorinated product
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What is the result of the following reaction?
What is the result of the following reaction?
Lithium Aluminum Hydride is a potent reducing agent; it has the ability to turn esters and aldehydes into primary alcohols, and ketones into secondary alcohols. The starting material is an aldehyde, so the correct answer is thus a primary alcohol ONLY.
Lithium Aluminum Hydride is a potent reducing agent; it has the ability to turn esters and aldehydes into primary alcohols, and ketones into secondary alcohols. The starting material is an aldehyde, so the correct answer is thus a primary alcohol ONLY.
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