Help with Radical Reactions - Organic Chemistry
Card 0 of 5
Which reagent must be used with hydrobromic acid to convert 1-hexene to 1-bromohexane?
Which reagent must be used with hydrobromic acid to convert 1-hexene to 1-bromohexane?
The double bond in 1-hexene is across carbons one and two. Just adding HBr would put the bromine on carbon 2 because the bromine is more stable on the more highly subtituted carbon. If you want to put the bromine on the less substituted carbon (generating 1-bromohexane), you must carry out the reaction in the presence of peroxides. The mechanism involves a free radical on the secondary carbon and a bromine addition on the primary carbon.
The double bond in 1-hexene is across carbons one and two. Just adding HBr would put the bromine on carbon 2 because the bromine is more stable on the more highly subtituted carbon. If you want to put the bromine on the less substituted carbon (generating 1-bromohexane), you must carry out the reaction in the presence of peroxides. The mechanism involves a free radical on the secondary carbon and a bromine addition on the primary carbon.
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Which site would the reagent N-Bromosuccinimide (NBS) be most likely to attack?
Which site would the reagent N-Bromosuccinimide (NBS) be most likely to attack?
The most substituted atom is most likely to be attacked, as a radical intermediate would be created. The radical intermediate would be most stable on the most substituted carbon.
The most substituted atom is most likely to be attacked, as a radical intermediate would be created. The radical intermediate would be most stable on the most substituted carbon.
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Which of the following reagents would create the product for the reaction below?
Which of the following reagents would create the product for the reaction below?
The radical reaction would create the anti-Markovnikov product shown and both 
, hv and 
, AIBN (azobisisobutyronitrile) effectively cause radical reactions. The bromine would then be substituted with the 
group.
The radical reaction would create the anti-Markovnikov product shown and both
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Which of these steps in a free-radical halogenation of an alkene will not generate a radical molecule?
Which of these steps in a free-radical halogenation of an alkene will not generate a radical molecule?
Termination is the only step that does not generate a radical product. The termination step ends the reaction by bringing together two radical molecules to produce a stable non-radical product.
Termination is the only step that does not generate a radical product. The termination step ends the reaction by bringing together two radical molecules to produce a stable non-radical product.
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Classify the type of reaction given.
Classify the type of reaction given.
Homolytic bond breaking occurs when a molecule breaks up to form two or more new products. In the reaction given, molecular chlorine forms two radicals in which one electron stays with each fragment formed.
Homolytic bond breaking occurs when a molecule breaks up to form two or more new products. In the reaction given, molecular chlorine forms two radicals in which one electron stays with each fragment formed.
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