Operations and Algebraic Thinking - MAP 6th Grade Math
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Solve for 
:
Solve for
In order to solve this equation we need to isolate the variable to one side. Do not forget to perform the same operation on both sides of the equation.
Divide each side of the equation by 
:
Solve.
In order to solve this equation we need to isolate the variable to one side. Do not forget to perform the same operation on both sides of the equation.
Divide each side of the equation by
Solve.
Compare your answer with the correct one above
Read the following scenario:
A barista has to make sixty pounds of a special blend of coffee at Moonbucks, using Hazelnut Happiness beans and Pecan Delight beans. If there are fourteen fewer pounds of Hazelnut Happiness beans in the mixture than Pecan Delight beans, then how many pounds of each will she use?
If 
represents the number of pounds of Pecan Delight coffee beans in the mixture, then which of the following equations could be set up in order to find the number of pounds of each variety of bean?
Read the following scenario:
A barista has to make sixty pounds of a special blend of coffee at Moonbucks, using Hazelnut Happiness beans and Pecan Delight beans. If there are fourteen fewer pounds of Hazelnut Happiness beans in the mixture than Pecan Delight beans, then how many pounds of each will she use?
If
Since there are fourteen fewer pounds of Hazelnut Happiness beans in the mixture than Pecan Delight beans , then the number of pounds of Hazelnut Happiness beans is fourteen subtracted from
:
.
Add the number of pounds of Pecan Delight beans, 
, to the number of pounds of Hazelnut Happiness beans, 
, to get the number of pounds of the mixture, which is 
.
This translates to the following equation:
Since there are fourteen fewer pounds of Hazelnut Happiness beans in the mixture than Pecan Delight beans , then the number of pounds of Hazelnut Happiness beans is fourteen subtracted from
Add the number of pounds of Pecan Delight beans,
This translates to the following equation:
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What is 
written as a multiplication problem?
What is
When expanding an exponent, we multiply the base by itself for the number indicated by the exponential value.
In this case, our base number is 
and our exponential value is 
. So we multiply 
by itself 
times.
Remember, the question asks us for the multiplication problem, not the answer to 
. Because of this, 
is our correct answer.
When expanding an exponent, we multiply the base by itself for the number indicated by the exponential value.
In this case, our base number is
Remember, the question asks us for the multiplication problem, not the answer to
Compare your answer with the correct one above