Card 0 of 7
Find the perimeter of the following box in inches:
The answer is .
You can find the perimeter by adding all of its respective sides as such:
.
Adding like terms will result in
If you chose , you multiplied the two sides to find the area.
If you chose , you only added two sides. Perimeter involves all 4 sides; so double the width and length.
Just remember, the width is 12 added to . Not 12 times the side of
.
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A parallelogram has an area of . If the height is
, what is the length of the base?
If the area of a parallelogram is given as with a height of
, we can refer back to the equation for the area of a parallelogram:
, where
is height and
is the length of the base.
This very quickly becomes a problem of substituting in values and finding the value of an unknown variable, in this case, :
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A parallelogram has a height of and an area of
. What is the length of the base of the parallelogram?
To find the missing side of this parallelgram apply the formula:
Thus, the solution is:
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A parallelogram has a base of and an area of
. What is the height of the parallelogram?
In order to find the height of this parallelogram apply the formula:
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Given that a parallelogram has a height of and an area of
. Find the base of the parallelogram.
In order to find the base of this parallelogram apply the formula:
Thus, the solution is:
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Quadrilateral is both a rhombus and a rectangle.
True or false: Quadrilateral must be a square.
A rhombus is defined to be a parallelogram with four congruent sides; a rectangle is defined to be a parallelogram with four right angles.
A square is defined to be a parallelogram with four congruent sides and four right angles. If a parallelogram is both a rhombus and a rectangle, then it fits both characteristics and is therefore a square.
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Given: Quadrilateral with diagonal
;
.
True or false: From the information given, it follows that Quadrilateral is a parallelogram.
Corresponding parts of congruent triangles are, by definition, congruent. Thus, from the statement , it follows that:
and
Quadrilateral therefore has two sets of congruent opposite sides. This is a sufficient condition for the quadrilateral to be a parallelogram.
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