Rational and radical equations Flashcards - HiSet: High School Equivalency Test: Math

$\sqrt[3]{5-2x}+5=4$

The first step to solving an equation where is in a radical is to isolate the radical. To do this, we need to subtract the 5 from both sides.

$\sqrt[3]{5-2x}+5-5=4-5$

$\sqrt[3]{5-2x}=-1$

Now that the radical is isolated, clear the radical by raising both sides to the power of 3. Note:

$(-1)^3 = -1 \cdot -1 \cdot -1 = -1$

$(\sqrt[3]{5-2x})^3=(-1)^3$

Now we want to isolate the term. First, subtract the 5 from both sides.

Finally, divide both sides by to solve for .

$\frac{-2x}{-2}=\frac{-6}{-2}$

Rational and radical equations - HiSet: High School Equivalency Test: Math