How to find the area of a kite - High School Math

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Question

What is the area of a kite with diagonals of 5 and 7?

Answer

To find the area of a kite using diagonals you use the following equation $\frac{ab}{2}=Area: of a: kite$

That diagonals ( and )are the lines created by connecting the two sides opposite of each other.

Plug in the diagonals for and to get $\frac{57}{2}=Area$

Then multiply and divide to get the area. $\frac{35}{2}=17.5$

The answer is

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Question

Find the area of the following kite:

Answer

The formula for the area of a kite is:

$A = \frac{1}{2}(d_{1}\cdot d_{2})$

Where $d_{1}$ is the length of one diagonal and $d_{2}$ is the length of the other diagonal

Plugging in our values, we get:

$A = \frac{1}{2}(d_{1}\cdot d_{2})$

$A = \frac{1}{2}(6m\cdot 13m) = 39m^2$

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Question

Find the area of the following kite:

Answer

The formula for the area of a kite is:

$A = \frac{1}{2} (d_1)(d_2)$

where is the length of one diagonal and is the length of another diagonal.

Use the formulas for a triangle and a triangle to find the lengths of the diagonals. The formula for a triangle is $a-a-a \sqrt{2}$ and the formula for a triangle is $a-a \sqrt{3}-2a$ .

Our triangle is: $3 \sqrt{2}m-3 \sqrt{2}m-6m$

Our triangle is: $3 \sqrt{2}m-3 \sqrt{6}m-6\sqrt{2}m$

Plugging in our values, we get:

$A = \frac{1}{2} (d_1)(d_2)$

$A = \frac{1}{2} (6\sqrt{2}m) (3\sqrt{6}m + 3\sqrt{2}m)$

$A = \frac{1}{2} (18\sqrt{12}+18\sqrt{4}) = 18\sqrt{3}+18m^2$

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