Graphing Circle Functions - High School Math
Card 0 of 2
Find the 
-intercepts for the circle given by the equation:
Find the
To find the 
-intercepts (where the graph crosses the 
-axis), we must set 
. This gives us the equation:
Because the left side of the equation is squared, it will always give us a positive answer. Thus if we want to take the root of both sides, we must account for this by setting up two scenarios, one where the value inside of the parentheses is positive and one where it is negative. This gives us the equations:
and 
We can then solve these two equations to obtain 
.
To find the
Because the left side of the equation is squared, it will always give us a positive answer. Thus if we want to take the root of both sides, we must account for this by setting up two scenarios, one where the value inside of the parentheses is positive and one where it is negative. This gives us the equations:
We can then solve these two equations to obtain
Compare your answer with the correct one above
Find the 
-intercepts for the circle given by the equation:
Find the
To find the 
-intercepts (where the graph crosses the 
-axis), we must set 
. This gives us the equation:
Because the left side of the equation is squared, it will always give us a positive answer. Thus if we want to take the root of both sides, we must account for this by setting up two scenarios, one where the value inside of the parentheses is positive and one where it is negative. This gives us the equations:
and 
We can then solve these two equations to obtain
To find the
Because the left side of the equation is squared, it will always give us a positive answer. Thus if we want to take the root of both sides, we must account for this by setting up two scenarios, one where the value inside of the parentheses is positive and one where it is negative. This gives us the equations:
We can then solve these two equations to obtain
Compare your answer with the correct one above