Finding Derivative of a Function - High School Math
Card 0 of 19
Find the derivative of the following function:
Find the derivative of the following function:
We use the power rule on each term of the function.
The first term
becomes
.
The second term
becomes
.
The final term, 7, is a constant, so its derivative is simply zero.
We use the power rule on each term of the function.
The first term
becomes
The second term
becomes
The final term, 7, is a constant, so its derivative is simply zero.
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Give the average rate of change of the function 
on the interval 
.
Give the average rate of change of the function
The average rate of change of 
on interval 
is
Substitute:
The average rate of change of
Substitute:
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What is the derivative of 
?
What is the derivative of
To get 
, we can use the power rule.
Since the exponent of the 
is 
, as 
, we lower the exponent by one and then multiply the coefficient by that original exponent:
Anything to the 
power is 
.
To get
Since the exponent of the
Anything to the
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What is the derivative of 
?
What is the derivative of
To solve this problem, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.
Remember that anything to the zero power is one.
To solve this problem, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.
Remember that anything to the zero power is one.
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What is the derivative of 
?
What is the derivative of
To solve this problem, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.
We're going to treat 
as 
, as anything to the zero power is one.
That means this problem will look like this:
Notice that 
, as anything times zero is zero.
Remember, anything to the zero power is one.
To solve this problem, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.
We're going to treat
That means this problem will look like this:
Notice that
Remember, anything to the zero power is one.
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What is the derivative of 
?
What is the derivative of
To solve this problem, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.
We're going to treat 
as 
, as anything to the zero power is one.
Notice that 
, as anything times zero is zero.
To solve this problem, we can use the power rule. That means we lower the exponent of the variable by one and multiply the variable by that original exponent.
We're going to treat
Notice that
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To solve this equation, we can use the power rule. To use the power rule, we lower the exponent on the variable and multiply by that exponent.
We're going to treat 
as 
since anything to the zero power is one.
 "\frac{\mathrm{d} }{\mathrm{d} x}(6x^2+8)=(2*6x^{2-1})+(0*8x^{0-1})")
Notice that 
since anything times zero is zero.
To solve this equation, we can use the power rule. To use the power rule, we lower the exponent on the variable and multiply by that exponent.
We're going to treat
Notice that
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What is the derivative of 
?
What is the derivative of
To solve this equation, we can use the power rule. To use the power rule, we lower the exponent on the variable and multiply by that exponent.
We're going to treat 
as 
since anything to the zero power is one.
Notice that 
since anything times zero is zero.
That leaves us with 
.
Simplify.
As stated earlier, anything to the zero power is one, leaving us with:
To solve this equation, we can use the power rule. To use the power rule, we lower the exponent on the variable and multiply by that exponent.
We're going to treat
Notice that
That leaves us with
Simplify.
As stated earlier, anything to the zero power is one, leaving us with:
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What is the derivative of 
?
What is the derivative of
To solve this equation, we can use the power rule. To use the power rule, we lower the exponent on the variable and multiply by that exponent.
We're going to treat 
as 
since anything to the zero power is one.
 "\frac{\mathrm{d} }{\mathrm{d} x}(12x^2+13x+4)=(2*12x^{2-1})+(1*13x^{1-1})+(0*4x^{0-1})")
Notice that 
since anything times zero is zero.
Just like it was mentioned earlier, anything to the zero power is one.
To solve this equation, we can use the power rule. To use the power rule, we lower the exponent on the variable and multiply by that exponent.
We're going to treat
Notice that
Just like it was mentioned earlier, anything to the zero power is one.
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What is the derivative of 
?
What is the derivative of
To take the derivative of this equation, we can use the power rule. The power rule says that we lower the exponent of each variable by one and multiply that number by the original exponent.
Simplify.
Remember that anything to the zero power is equal to one.
To take the derivative of this equation, we can use the power rule. The power rule says that we lower the exponent of each variable by one and multiply that number by the original exponent.
Simplify.
Remember that anything to the zero power is equal to one.
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What is the derivative of 
?
What is the derivative of
To take the derivative of this equation, we can use the power rule. The power rule says that we lower the exponent of each variable by one and multiply that number by the original exponent.
We are going to treat 
as 
since anything to the zero power is one.
Notice that 
since anything times zero is zero.
Simplify.
As stated before, anything to the zero power is one.
To take the derivative of this equation, we can use the power rule. The power rule says that we lower the exponent of each variable by one and multiply that number by the original exponent.
We are going to treat
Notice that
Simplify.
As stated before, anything to the zero power is one.
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What is the derivative of 
?
What is the derivative of
To find the first derivative, we can use the power rule. We lower the exponent on all the variables by one and multiply by the original variable.
Anything to the zero power is one.
To find the first derivative, we can use the power rule. We lower the exponent on all the variables by one and multiply by the original variable.
Anything to the zero power is one.
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What is the derivative of 
?
What is the derivative of
To find the first derivative, we can use the power rule. We lower the exponent on all the variables by one and multiply by the original variable.
We're going to treat 
as 
since anything to the zero power is one.
For this problem that would look like this:
Notice that 
since anything times zero is zero.
To find the first derivative, we can use the power rule. We lower the exponent on all the variables by one and multiply by the original variable.
We're going to treat
For this problem that would look like this:
Notice that
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What is the derivative of 
?
What is the derivative of
To find the first derivative, we can use the power rule. To do that, we lower the exponent on the variables by one and multiply by the original exponent.
We're going to treat 
as 
since anything to the zero power is one.
 "\frac{\mathrm{d} }{\mathrm{d} x}(x^3+2x^2+5)=(3*x^{3-1})+(2*2x^{2-1})+(0*5x^{0-1})")
Notice that 
since anything times zero is zero.
To find the first derivative, we can use the power rule. To do that, we lower the exponent on the variables by one and multiply by the original exponent.
We're going to treat
Notice that
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What is the first derivative of 
?
What is the first derivative of
To find the first derivative for this problem, we can use the power rule. The power rule states that we lower the exponent of each of the variables by one and multiply by that original exponent.
Remember that anything to the zero power is one.
To find the first derivative for this problem, we can use the power rule. The power rule states that we lower the exponent of each of the variables by one and multiply by that original exponent.
Remember that anything to the zero power is one.
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This problem is best solved by using the power rule. For each variable, multiply by the exponent and reduce the exponent by one:
Treat 
as 
since anything to the zero power is one.
Remember, anything times zero is zero.
This problem is best solved by using the power rule. For each variable, multiply by the exponent and reduce the exponent by one:
Treat
Remember, anything times zero is zero.
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To find the derivative of the problem, we can use the power rule. The power rule says to multiply the coefficient of the variable by the exponent of the variable and then lower the exponent value by one.
To make that work, we're going to treat 
as 
, since anything to the zero power is one.
This means that 
is the same as 
.
Now use the power rule:
Anything times zero is zero.
To find the derivative of the problem, we can use the power rule. The power rule says to multiply the coefficient of the variable by the exponent of the variable and then lower the exponent value by one.
To make that work, we're going to treat
This means that
Now use the power rule:
Anything times zero is zero.
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What is the first derivative of 
?
What is the first derivative of
To find the derivative of 
, we can use the power rule.
The power rule states that we multiply each variable by its current exponent and then lower the exponent of each variable by one.
Since 
, we're going to treat 
as 
.
Anything times zero is zero, so our final term 
, regardless of the power of the exponent.
Simplify what we have.
Our final solution, then, is 
.
To find the derivative of
The power rule states that we multiply each variable by its current exponent and then lower the exponent of each variable by one.
Since
Anything times zero is zero, so our final term
Simplify what we have.
Our final solution, then, is
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If 
, what is 
?
If
For this problem, we can use the power rule. The power rule states that we multiply each variable by its current exponent and then lower that exponent by one.
Simplify.
Anything to the zero power is one, so 
.
Therefore, 
.
For this problem, we can use the power rule. The power rule states that we multiply each variable by its current exponent and then lower that exponent by one.
Simplify.
Anything to the zero power is one, so
Therefore,
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