Right Triangles - GRE Quantitative Reasoning

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Question

A triangle has three internal angles of 75, 60, and x. What is x?

Answer

The internal angles of a triangle must add up to 180. 180 - 75 -60= 45.

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Question

Quantitative Comparison

Quantity A: The area of a triangle with a perimeter of 34

Quantity B: 30

Answer

A triangle with a fixed perimeter does not have to have a fixed area. For example, a triangle with sides 3, 4, and 5 has a perimeter of 12 and an area of 6. A triangle with sides 4, 4, and 4 also has a perimeter of 12 but not an area of 6. Thus the answer cannot be determined.

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Question

Quantitative Comparison

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Column A

Area

Column B

Perimeter

  

Answer

To find the perimeter, add up the sides, here 5 + 12 + 13 = 30. To find the area, multiply the two legs together and divide by 2, here (5 * 12)/2 = 30.

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Question

Gre_quant_179_01

Given triangle ACE where B is the midpoint of AC, what is the area of triangle ABD?

Answer

If B is a midpoint of AC, then we know AB is 12. Moreover, triangles ACE and ABD share angle DAB and have right angles which makes them similar triangles. Thus, their sides will all be proportional, and BD is 4. 1/2bh gives us 1/2 * 12 * 4, or 24.

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Question

What is the area of a right triangle with hypotenuse of 13 and base of 12?

Answer

Area = 1/2(base)(height). You could use Pythagorean theorem to find the height or, if you know the special right triangles, recognize the 5-12-13. The area = 1/2(12)(5) = 30.

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Question

Quantitative Comparison

Quantity A: the area of a right triangle with sides 10, 24, 26

Quantity B: twice the area of a right triangle with sides 5, 12, 13

Answer

Quantity A: area = base * height / 2 = 10 * 24 / 2 = 120

Quantity B: 2 * area = 2 * base * height / 2 = base * height = 5 * 12 = 60

Therefore Quantity A is greater.

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Question

Quantitative Comparison

Quantity A: The area of a triangle with a height of 6 and a base of 7

Quantity B: Half the area of a trapezoid with a height of 6, a base of 6, and another base of 10

Answer

Quantity A: Area = 1/2 * b * h = 1/2 * 6 * 7 = 42/2 = 21

Quantity B: Area = 1/2 * (_b_1 + _b_2) * h = 1/2 * (6 + 10) * 6 = 48

Half of the area = 48/2 = 24

Quantity B is greater.

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Question

The radius of the circle is 2. What is the area of the shaded equilateral triangle?

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Answer

This is easier to see when the triangle is divided into six parts (blue). Each one contains an angle which is half of 120 degrees and contains a 90 degree angle. This means each triangle is a 30/60/90 triangle with its long side equal to the radius of the circle. Knowing that means that the height of each triangle is \dpi{100} \small \frac{r\sqrt{3}}{2} and the base is \dpi{100} \small \frac{r}{2}.

Applying \dpi{100} \small \frac{bh}{2} and multiplying by 6 gives \dpi{100} \small 3\sqrt{3}).

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Question

An equilateral triangle has a side length of 4. What is its height?

Answer

If an equilateral triangle is divided in 2, it forms two 30-60-90 triangles. Therefore, the side of the equilateral triangle is the same as the hypotenuse of a 30-60-90 triangle. The side lengths of a 30-60-90 triangle adhere to the ratio x: x√3 :2x. since we know the hypothesis is 4, we also know that the base is 2 and the height is 2√3.

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Question

Each of the following answer choices lists the side lengths of a different triangle. Which of these triangles does not have a right angle?

Answer

cannot be the side lengths of a right triangle. does not equal . Also, special right triangle and rules can eliminate all the other choices.

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Question

Daria and Ashley start at the same spot and walk their two dogs to the park, taking different routes. Daria walks 1 mile north and then 1 mile east. Ashley walks her dog on a path going northeast that leads directly to the park. How much further does Daria walk than Ashley?

Answer

First let's calculate how far Daria walks. This is simply 1 mile north + 1 mile east = 2 miles. Now let's calculate how far Ashley walks. We can think of this problem using a right triangle. The two legs of the triangle are the 1 mile north and 1 mile east, and Ashley's distance is the diagonal. Using the Pythagorean Theorem we calculate the diagonal as √(12 + 12) = √2. So Daria walked 2 miles, and Ashley walked √2 miles. Therefore the difference is simply 2 – √2 miles.

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Question

Which of the following sets of sides cannnot belong to a right triangle?

Answer

To answer this question without plugging all five answer choices in to the Pythagorean Theorem (which takes too long on the GRE), we can use special triangle formulas. Remember that 45-45-90 triangles have lengths of x, x, x√2. Similarly, 30-60-90 triangles have lengths x, x√3, 2x. We should also recall that 3,4,5 and 5,12,13 are special right triangles. Therefore the set of sides that doesn't fit any of these rules is 6, 7, 8.

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Question

Max starts at Point A and travels 6 miles north to Point B and then 4 miles east to Point C. What is the shortest distance from Point A to Point C?

Answer

This can be solved with the Pythagorean Theorem.

62 + 42 = _c_2

52 = _c_2

c = √52 = 2√13

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Question

Which set of side lengths CANNOT correspond to a right triangle?

Answer

Because we are told this is a right triangle, we can use the Pythagorean Theorem, _a_2 + _b_2 = _c_2. You may also remember some of these as special right triangles that are good to memorize, such as 3, 4, 5.

Here, 6, 8, 11 will not be the sides to a right triangle because 62 + 82 = 102.

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Question

Kathy and Jill are travelling from their home to the same destination. Kathy travels due east and then after travelling 6 miles turns and travels 8 miles due north. Jill travels directly from her home to the destination. How miles does Jill travel?

Answer

Kathy's path traces the outline of a right triangle with legs of 6 and 8. By using the Pythagorean Theorem

\dpi{100} \small 6^{2}+8^{2}=x^{2}

\dpi{100} \small 36+64=x^{2}

\dpi{100} \small x=10 miles

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Question

Square is on the coordinate plane, and each side of the square is parallel to either the -axis or -axis. Point has coordinates and point has the coordinates .

Quantity A: 5\sqrt{2}

Quantity B: The distance between points and

Answer

To find the distance between points and , split the square into two 45-45-90 triangles and find the hypotenuse. The side ratio of the 45-45-90 triangle is , so if the sides have a length of 5, the hypotenuse must be 5\sqrt{2}.

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Question

2 triangles are similar

Triangle 1 has sides 6, 8, 10

Triangle 2 has sides 5 , 3, x

find x

Answer

Draw the triangles

Triangle 1 is a 6,8,10 right triangle with 10 as the hypotenuse

Triangle 2: 3 is half of 6, 5 is half of 10; x must be half of 8

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Question

Varsity_tutors_problem1

Given the diagram, indicate if Quantity A is larger, Quantity B is larger, if they are equal, or if there is not enough information given to determine the relationship.

Quantity A: \dpi{100} \small x

Quantity B: 7.5

Answer

Since this is a 30-60-90 triangle, we know that the length of the side opposite the 60 degree angle is \dpi{100} \small \sqrt{3} times the side opposite the 30 degree angle. Thus, \dpi{100} \small 5\sqrt{3}, which is about 8.66. This is larger than 7.5.

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Question

A right triangle's perimeter is \dpi{100} \small 3+\sqrt{3}. The other two angles of the triangle are 30 degrees and 60 degrees.

Quantity A: The triangle's hypotenuse length

Quantity B: 2

Answer

The ratio of the sides of a 30-60-90 triangle is \dpi{100} \small x:x{\sqrt{3}}:2x, with the hypotenuse being \dpi{100} \small 2x. Thus, the perimeter of this triangle would be \dpi{100} \small x+x\sqrt{3}+2x=3x\sqrt{3}. Since the triangle depicted in this problem has a perimeter of \dpi{100} \small 3\sqrt{3}, \dpi{100} \small x must equal 1, which would make the hypotenuse equal to 2.

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Question

If the shortest side of a right triangle has length and its hypotenuse has length , what is the length of the remaining side?

Answer

Use the Pythagorean theorem, a^2 + b^2 = c^2 , with \dpi{100} \small a=x-4 and \dpi{100} \small c=x+4, and solve for \dpi{100} \small b.

(x-4)^2 + b^2 = (x+4)^2

Rearrange to isolate \dpi{100} \small b^{2}:

b^2 = (x+4)^2 - (x-4)^2

b^2 = (x+4)(x+4) - (x-4)(x-4)

Use FOIL to multiply out:

b^2 = (x^2 + 8x + 16) - (x^2 - 8x + 16)

Distribute the minus sign to rewrite without parentheses:

b^2 = x^2 + 8x + 16 - x^2 + 8x - 16

Combine like terms:

b^2 = 16x

Take the square root of both sides:

b = 4\sqrt{x}

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