Sets - GMAT Quantitative Reasoning

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Question

Define two sets as follows:

where and are distinct positive odd integers and and are distinct positive even integers.

How many elements are contained in the set ?

Answer

Suppose we know , but we do not assume the second statement.

If and , then , a four-element set. If If and , then , a three-element set. Therefore, we cannot make a conclusion about the size of . A similar argument can be used to show that assuming only the second statement also does not allow a conclusion.

If we know both statements, however, , and we can prove that has four elements.

The answer is that both statements together are sufficient to answer this question, but neither statement alone is sufficient.

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Question

True or false:

Statement 1: is a perfect square.

Statement 2: is a multiple of 99.

Answer

includes all multiples of 2; includes all multiples of 3. comprises all multiples of either 2 or 3.

Knowing is a perfect square is neither necessary nor helpful, as, for example, , but (as 25 is neither a multiple of 2 nor a multiple of 3).

If you know that is a multiple of 99, then it must also be a multiple of any number that divides 99 evenly, one such number is 3. This means

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Question

How many elements are in the set ?

Statement 1: has three more elements than .

Statement 2: includes exactly four elements not in .

Answer

Assume both statements are true.

Consider these two cases:

Case1: and

Case 2: and

In both situations, has three more elements than and includes exactly four elements not in (1, 2, 3 and 4). However, the number of elements in the union differ in each case - in the first case, , and in the second case, .

The two statements together do not yield an answer to the question.

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Question

Venn_1

In the above Venn diagram, universal set represents the residents of Jonesville. The sets represent the set of all Toastmasters, Elks, and Masons, respectively.

Jerry is a resident of Jonesville. Is he a Mason?

Statement 1: Jerry is a Toastmaster.

Statement 2: Jerry is not an Elk.

Answer

The question is equivalent to asking whether Jerry is an element of set .

The sets and are disjoint - they have no elements in common. From Statement 1 alone, Jerry is an element of , so he cannot be an element of . He is not a Mason.

From Statement 2 alone, Jerry is an element of . Since there are elements not in that are and are not elements of , it cannot be determined whether Jerry is an element of - a Mason.

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Question

Venn_1

In the above Venn diagram, universal set represents the residents of a city. The sets represent the set of all teenagers, even birth month, and males, respectively.

Jamie is a resident of this city. Does Jamie have an even birth month?

Statement 1: Jamie is not a male.

Statement 2: Jamie is not a teenager.

Answer

The question is whether or not Jamie is an element of .

Assume both statements to be true. Then Jamie is an element of the set , shaded in this Venn diagram:

Venn_1

Some elements of are elements of , but some are not, making the two statements together insufficient to answer the question of whether Jamie is an element of . Whether Jamie was born in an even month or not cannot be determined.

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Question

Venn_1

In the above Venn diagram, universal set represents the residents of Eastland. The sets represent the set of all Toastmasters, Elks, and Masons, respectively.

Craig is a resident of Eastland. Is Craig a Toastmaster?

Statement 1: Craig is not a Mason.

Statement 2: Craig is not an Elk.

Answer

The question is whether or not Craig is an element of .

Assume both statements to be true. Craig is an element of the set , shaded in this Venn diagram:

Venn_1

There are elements of this set that both are and are not elements of . Therefore, the two statements together do not prove or disprove Craig to be an element of , a Toastmaster.

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Question

Venn_1

In the above Venn diagram, universal set represents the residents of Jacksonville. The sets represent the set of all Toastmasters, Elks, and Masons, respectively.

Jimmy is a resident of Jacksonville. Is Jimmy a Mason?

Statement 1: Jimmy is not a Toastmaster.

Statement 2: Jimmy is not an Elk.

Answer

The question asks whether Jimmy is an element of .

Statement 1 alone - that Jimmy is an element of - provides insufficient information, since contains elements that are and are not elements of . By a similar argument, Statement 2 alone is insufficient.

Now assume both statements to be true. Then Jimmy is an element of , shaded in the Venn diagram below:

Venn_1

It can be seen that shares no elements with , so Jimmy cannot be an element of . Jimmy is not a Mason.

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Question

Two of the courses from which the 98 freshmen at a high school may choose are French and Creative Writing.

How many freshmen enrolled in neither course?

Statement 1: 10 freshmen enrolled in both courses.

Statement 2: 21 freshmen enrolled in each course.

Answer

The question asks for the number of students in the set , where and are the sets of students who took French and Creative Writing, respectively.

From Statement 1 alone, a Venn diagram representing this situation can be filled in as follows:

Venn_1

It is known that ; subsequently, . But no other information is given, so , the desired quantity, cannot be calculated.

From Statement 2 alone, a Venn diagram representing this situation can be filled in as follows:

Venn_1

Again, no further information can be computed.

Now assume that both statements are true. Then it follows from Statement 1 that , and it follows from Statement 2 that the desired quantity is

.

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Question

Venn_1

In the above Venn diagram, universal set represents the residents of Wayne. The sets represent the set of all teenagers, those with an even birth month, and males, respectively.

Cary is a resident of Wayne. Is Cary a male?

Statement 1: Cary is a teenager.

Statement 2: Cary does not have an even birth month.

Answer

The question asks if Cary is an element of .

Assume Statement 1 alone. From the Venn diagram, it can be seen that and are disjoint sets. Since Cary is an element of , he cannot be an element of - Cary is not a Male.

Assume Statement 2 alone. From the Venn diagram, it can be seen that - that is, if Cary is an element of , then she is an element of . Restated, if Cary is a Male, then he is a Teenagers. The contrapositive also holds - if Cary is not a teenager - which is given in Statement 2 - then Cary is not a male.

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Question

Venn_1

In the above Venn diagram, universal set represents the residents of Belleville. The sets represent the set of all Toastmasters, Elks, and Masons, respectively.

Marty is a resident of Belleville. Is he an Elk?

Statement 1: Marty is neither a Mason nor a Toastmaster.

Statement 2: Marty belongs to exactly one of the three groups.

Answer

The question asks whether or not Marty is an element of .

Assume Statement 1 alone. He is an element of , represented by the shaded region below:

Venn_1

includes elements that are and are not elements of , so it cannot be determined whether or not Marty is in .

Assume Statement 2 alone. Then Marty has to be an element of the set represented by the shaded region below:

Venn_1

Since some of the set is in and some is not, it cannot be determined whether or not Marty is in .

If both statements are known, then, since Marty is in exactly one of the three sets, and he is not a Mason or a Toastmaster, then he must be an Elk.

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Question

Two of the courses from which the 106 freshmen at Jefferson Academy may choose are American literature and German.

How many freshmen enrolled in both courses?

Statement 1: 19 freshment enrolled in German.

Statement 2: 21 freshmen enrolled in American literature.

Answer

Assume both statements are true. If is the number of students enrolled in both courses, we can fill in the Venn diagram for the situation with the expressions shown:

Venn_1

No further information is given in the problem, however, so there is no way to calculate .

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Question

Let universal set be the set of all people. Let represent Frank.

Let be the set of all people who like tea. Let be the set of all people who like coffee.

True or false: .

Statement 1: Frank likes tea.

Statement 2: Frank likes coffee.

Answer

is the union of the set , the set of all people who like coffee, and , the complement of the set of all people who like tea - that is, the set of all people who do not like tea. if either Frank likes coffee or Frank does not like tea or both.

Statement 1 alone, that Frank likes tea, does not prove or disprove this to be true true; if Frank likes coffee, then this is true, and if he does not like coffee, then this is not true. Statement 2 alone, however, proves this statement true.

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Question

Let universal set be the set of all people. Let represent Gina.

Let be the set of all people who like cheddar cheese. Let be the set of all people who like Swiss cheese.

True or false: .

Statement 1: Gina likes cheddar cheese.

Statement 2: Gina does not like Swiss cheese.

Answer

is the intersection of , the complement of the set of people who like cheddar cheese - that is, the set of people who don't like cheddar cheese - and , the set of people who like Swiss cheese. For to be true, it must hold that Gina doesn't like cheddar cheese and Gina likes Swiss cheese. Either statement alone makes this false.

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Question

Let universal set be the set of all people. Let represent Holly.

Let be the set of people who like The Eagles, , the set of people who like Bruce Springsteen, and , the set of people who like Crosby, Stills, and Nash.

True or false: Holly likes The Eagles.

Statement 1:

Statement 2:

Answer

Assume Statement 1 alone. is the intersection of two sets - and , the complements of, respectively, the set of people who like The Eagles and the set of people who like Bruce Springsteen. Equivalently, this is the intersection of the set of people who do not like The Eagles and the set of people who do not like Bruce Springsteen. Since , Holly falls in both sets. Specifically, she does not like The Eagles.

Assume Statement 2 alone. is the union of two sets - , the set of people who do not like The Eagles and , the set of people who like Crosby, Stills, and Nash. If , Holly falls in either or both sets, so either she doesn't like The Eagles, or she likes Crosby, Stills, and Nash, or both. It is not resolved whether she likes The Eagles or not.

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Question

Let universal set be the set of all people. Let represent Veronica.

Let be the set of people who like Pearl Jam, , the set of people who like Nirvana, and , the set of people who like Soundgarden.

True or false: Veronica likes at least two of Pearl Jam, Nirvana, and Soundgarden.

Statement 1:

Statement 2:

Answer

Assume both statements to be true.

is the union of the sets , , and ; Veronica falls in this union, so she falls in at least one of the three sets, so she likes one, two, or all three of Pearl Jam, Nirvana, and Soundgarden.

Similarly, from Statement 2, Veronica falls in at least one of the three sets , , and - the complements of the three sets - meaning that she doesn't like at least one of the three. Therefore, Veronica likes none, one, or two of the artists.

From the two statements together, it follows that Veronica likes one or two of the artists. Without further information, however, it cannot be determined whether she likes two of the artists.

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Question

Let universal set be the set of all people. Let represent Phillip.

Let be the set of people who like Neil Young, , the set of people who like Prince, and , the set of people who like Marvin Gaye.

True or false: Phillip does not like Neil Young, Prince, or Marvin Gaye.

Statement 1:

Statement 2:

Answer

Assume Statement 1 alone. is the intersection of the complements of all three of , , and - the sets of people who do not like Neil Young, people who do not like Prince, and people who do not like Marvin Gaye. Any person who is in this intersection does not like any of these three. , so Phillip does not like Neil Young, Prince, or Marvin Gaye.

Assume Statement 2 alone. is the union of all three , , and . Any person who is in this union likes any one, two, or three of these musicians. However, , which is the complement of this union - the set of people who like none of Neil Young, Prince, or Marvin Gaye. Phil is in this set.

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Question

Every Bee is a Cee. Every Dee is a Cee. Every Cee is a Fee.

True or false: Bumpy is a Fee.

Statement 1: Bumpy is not a Dee.

Statement 2: Bumpy is not a Bee.

Answer

and .

This can be respresented in a Venn diagram as follows:

Venn 2

Assume both statements to be true. If we let represent Bumpy, then from the diagram, it can be seen that if Bumpy is neither a Bee or a Dee, it is possible for Bumpy to be be a Fee or to not be a Fee.

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Question

Every Beep is a Deep. Every Deep is a Meep. No Veep is a Deep.

Is Harpy a Veep?

Statement 1: Harpy is a Meep.

Statement 2: Harpy is a Beep.

Answer

Assume Statement 1 alone. Let represent the sets of Beeps, Deeps, Meeps, and Veeps. Then and, since all Veeps are not Deeps, . This is represented by the Venn diagram below:

Untitled

Note that the set (Meeps) need not fall completely inside the set (Veeps). Therefore, Harpy being a Meep does not necessarily make him a Veep or not a Veep.

Assume Statement 2 alone. Every Beep is a Deep, but no Veep is a Deep. If Harpy is a Beep, then he is a Deep. If Harpy were a Veep, then he cannot be a Deep, so, by contradiction, Harpy cannot be a Veep.

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Question

No Fee is a Fi. No Fi is a Fo. No Fo is a Fum.

True or false: Jack is a Fum.

Statement 1: Jack is not a Fo.

Statement 2: Jack is not a Fi.

Answer

Let be the sets of Fe's, Fi's, Fo's and Fum's, respectively. According to the premise of the problem, the sets and are disjoint (they have no elements in common); the sets and are disjoint; and the sets and are disjoint. No other relationships are known. A Venn diagram of these relationships is below:

Venn 2

Assume both statements to be true. The question is whether or not Jack falls in set . If Jack is neither a Fi nor a Fo, then Jack falls in neither set nor set . As evidenced by the two X's in the diagram, it is possible for Jack to fall in set or to not fall in set . Therefore, the question of whether Jack is a Fum is unresolved.

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Question

Everyone in Jonesville likes exactly three of the following - apples, bananas, cranberries, dates, figs, and guavas. No one in Jonesville who likes apples also likes guavas. No one in Jonesville who likes bananas also likes figs. No one in Jonesville who likes cranberries also likes dates.

Smith lives in Jonesville. True or false: Smith likes figs.

Statement 1: Smith doesn't like bananas.

Statement 2: Smith doesn't like cranberries.

Answer

Let represent the sets of people who like apples, bananas, etc. , respectively. Let represent Smith.

Assume Statement 1 alone.

If , then . Contrapositively, if , then . Therefore, cannot be in both and ; is in one, the other, or neither. By similar reasoning, is in at most one of and and at most one of and .

Suppose and . Then is in three of , and either falls in both and or both and ; since both are impossible, it follows that or , but not both. Therefore, Smith likes exactly one of bananas and figs, but not both. Since, from Statement 1, Smith doesn't like bananas, he must like figs.

Assume Statement 2. By similar reasoning, Smith likes cranberries or dates, but not both. Since he does not like cranberries, he likes dates. However, without further information, it cannot be determined what else he likes or dislikes.

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