Card 0 of 6
Solve for in the coordinate
on line
?
To solve for for
, we have to plug
into the
variable of the equation and solve for
:
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Solve for in the coordinate
on line
?
To solve for for
, we have to plug 1 into the
variable of the equation and solve for
:
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Solve for in the coordinate
on line
?
To solve for for
, we have to plug
into the
variable of the equation and solve for
:
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Consider segment which passes through the points
and
.
If the point is on
, what is the value of y?
First, use the points to find the equation of JK:
Given that JK passes through (4,5) and (144,75) we can find the slope as follows:
Slope is found via:
Plug in and calculate:
Next, we need to use one of our points and the slope to find our y-intercept. I'll use (4,5).
So our answer is:
To find y, we need to plug in 16 for x and solve:
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If is defined as follows, is the point
on
?
To find out if (-2,5) is on f(x), simply plug the point into f(x)
Becomes,
So yes, it does!
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Which of the following are points along if
.
One way to solve this one is by plugging in each of the answer choices and eliminating any that don't work out. Begin with our original g(x)
If we plug in 3 we get
,
So our point is (3,28).
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