Apply Density Concepts to Area and Volume Situations: CCSS.Math.Content.HSG-MG.A.2 - Common Core: High School - Geometry

Card 0 of 12

Question

If a balloon is filled with 58398 cubic meters of xenon with a density of 0.1629 kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to 2 decimal places

Answer

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ( $\uptext{m}$ ).

$0.1629 = \frac{m}{58398}$

Thus the mass of the balloon is 9513.03 kilograms.

Compare your answer with the correct one above

Question

If a balloon is filled with cubic meters of xenon with a density of kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to decimal places

Answer

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ( $\uptext{m}$ ).

$0.1629 = \frac{m}{58398}$

Thus the mass of the balloon is $9513.03 \text{ kilograms}$ .

Compare your answer with the correct one above

Question

If a balloon is filled with cubic meters of xenon with a density of kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to decimal places.

Answer

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\0.9606 = \frac{m}{53678} \\m = 51563.09$

Thus the mass of the balloon is $51563.09 \text{ kilograms}$ .

Compare your answer with the correct one above

Question

If a balloon is filled with cubic meters of xenon with a density of kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to decimal places.

Answer

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ( $\uptext{m}$ ).

$\0.1417 = \frac{m}{58744} \\m = 8324.02$

Thus the mass of the balloon is $8324.02 \text{ kilograms}$ .

Compare your answer with the correct one above

Question

If a balloon is filled with cubic meters of xenon with a density of kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to decimal places.

Answer

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\0.5102 = \frac{m}{86938} \\m = 44355.77$

Thus the mass of the balloon is $44355.77 \text{ kilograms}$ .

Compare your answer with the correct one above

Question

If a balloon is filled with cubic meters of neon with a density of kilograms per cubic meter. How many kilograms of neon does the balloon contain?

Round your answer to decimal places.

Answer

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\0.0364 = \frac{m}{72481} \\m = 2638.31$

Thus the mass of the balloon is $2638.31 \text{ kilograms}$ .

Compare your answer with the correct one above

Question

If a balloon is filled with cubic meters of water with a density of kilograms per cubic meter. How many kilograms of water does the balloon contain?

Round your answer to decimal places.

Answer

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\0.011 = \frac{m}{78453} \\m = 862.98$

Thus the mass of the balloon is $862.98 \text{ kilograms }$ .

Compare your answer with the correct one above

Question

If a balloon is filled with cubic meters of neon with a density of kilograms per cubic meter. How many kilograms of neon does the balloon contain?

Round your answer to decimal places.

Answer

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\0.3281 = \frac{m}{52097} \\m = 17093.03$

Thus the mass of the balloon is $17093.03 \text{ kilograms}$ .

Compare your answer with the correct one above

Question

If a balloon is filled with cubic meters of water with a density of kilograms per cubic meter. How many kilograms of water does the balloon contain?

Round your answer to decimal places.

Answer

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\0.4689 = \frac{m}{77003} \\m = 36106.71$ Thus the mass of the balloon is $36106.71 \text{ kilograms}$ .

Compare your answer with the correct one above

Question

If a balloon is filled with cubic meters of xenon with a density of kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to decimal places.

Answer

In order to solve this problem, we need to use an equation that involves, density, mass, and volume. Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\0.183 = \frac{m}{97999} \\m = 17933.82$

Thus the mass of the balloon is $17933.82 \text{ kilograms}$ .

Compare your answer with the correct one above

Question

If a balloon is filled with cubic meters of neon with a density of kilograms per cubic meter. How many kilograms of neon does the balloon contain?

Round your answer to decimal places.

Answer

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\0.2245 = \frac{m}{70672} \\m = 15865.86$

Thus the mass of the balloon is $15865.86 \text{ kilograms}$ .

Compare your answer with the correct one above

Question

If a balloon is filled with cubic meters of water with a density of kilograms per cubic meter. How many kilograms of water does the balloon contain?

Round your answer to decimal places.

Answer

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\0.6665 = \frac{m}{86486} \\m = 57642.92$

Thus the mass of the balloon is $57642.92 \text{ kilograms}$ .

Compare your answer with the correct one above

Tap the card to reveal the answer