Derive Parabola Equation: CCSS.Math.Content.HSG-GPE.A.2

Practice Questions

Common Core: High School - Geometry › Derive Parabola Equation: CCSS.Math.Content.HSG-GPE.A.2

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1

Find the parabolic equation, where the focus and directrix are as follows.

$\\text{focus}= \left ( -6, 1\right ) \\text{directrix } y = -5$

2

Find the parabolic equation, where the focus and directrix are as follows.

$\\text{focus}= \left ( 1, -6\right ) \\text{directrix} y = -19$

3

Find the parabolic equation, where the focus and directrix are as follows.

$\\text{focus}= \left ( 6, -9\right ) \ \text{directrix } y = -5$

4

Find the parabolic equation, where the focus and directrix are as follows.

$\\text{focus}= \left ( 2, 5\right ) \\text{directrix } y = -6$

5

Find the parabolic equation, where the focus and directrix are as follows.

$\\text{focus}= \left ( -10, 6\right ) \ \text{directrix } y = 15$

6

Find the parabolic equation, where the focus and directrix are as follows.

$\\text{focus}= \left ( -6, 6\right ) \\text{directrix } y = -6$

7

Find the parabolic equation, where the focus and directrix are as follows.

$\\text{focus}= \left ( -10, 4\right ) \ \text{directrix } y = -11$

8

Find the parabolic equation, where the focus and directrix are as follows.

$\\text{focus}= \left ( -10, -3\right ) \\text{directrix } y = -4$

9

Find the parabolic equation, where the focus and directrix are as follows.

$\\text{focus}= \left ( 7, 5\right ) \\text{directrix } y = -4$

10

Find the parabolic equation, where the focus and directrix are as follows.

$\\text{focus}= \left ( -8, 9\right ) \\text{directrix } y = 12$

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