Describe Situations in Which Opposite Quantities Combine to Make 0: CCSS.Math.Content.7.NS.A.1a - Common Core: 7th Grade Math

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Question

Compute the following:

Answer

Convert all the double signs to a single sign before solving. Remember, two minus (negative) signs combine to form a plus (positive) sign, and a plus (positive) sign and a minus (negative) sign combine to form a minus (negative) sign.

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Question

Which value, when substituted for x, will make the equation true?

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}15-x=0\ +x+x\end{array}}{\\15=x}$

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Question

For the equation provided, what value, when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}7-x=0\ +x+x\end{array}}{\\7=x}$

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Question

For the equation provided, what value, when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}13-x=0\ +x+x\end{array}}{\\13=x}$

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Question

For the equation provided, what value, when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}27-x=0\ +x+x\end{array}}{\\27=x}$

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Question

For the equation provided, what value, when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}34-x=0\ +x+x\end{array}}{\\34=x}$

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Question

For the equation provided, what value, when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}6-x=0\ +x+x\end{array}}{\\6=x}$

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Question

For the equation provided, what value, when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}94-x=0\ +x+x\end{array}}{\\94=x}$

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Question

For the equation provided, what value, when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}83-x=0\ +x+x\end{array}}{\\83=x}$

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Question

For the equation provided, what value, when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}75-x=0\ +x+x\end{array}}{\\75=x}$

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Question

For the equation provided, what value, when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}66-x=0\ +x+x\end{array}}{\\66=x}$

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Question

For the equation provided, what value, when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}59-x=0\ +x+x\end{array}}{\\59=x}$

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Question

For the equation provided, what value, when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}46-x=0\ +x+x\end{array}}{\\46=x}$

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Question

For the equation provided, what value when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}11+x=0\ -11\ \ \ \ -11\end{array}}{\\x=-11}$

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Question

For the equation provided, what value when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}24+x=0\ -24\ \ \ \ -24\end{array}}{\\x=-24}$

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Question

For the equation provided, what value when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}38+x=0\ -38\ \ \ \ -38\end{array}}{\\x=-38}$

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Question

For the equation provided, what value, when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract from both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}40+x=0\ -40\ \ \ \ -40\end{array}}{\\x=-40}$

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Question

For the equation provided, what value when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}59+x=0\ -59\ \ \ \ -59\end{array}}{\\x=-59}$

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Question

For the equation provided, what value when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}62+x=0\ -62\ \ \ \ -62\end{array}}{\\x=-62}$

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Question

For the equation provided, what value when substituted for , will equal

Answer

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}70+x=0\ -70\ \ \ \ -70\end{array}}{\\x=-70}$

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