Add up to Four Two-Digit Numbers: CCSS.Math.Content.2.NBT.B.6 - Common Core: 2nd Grade Math

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Question

Solve the following:

$\frac{\begin{array}[b]{r}87\30\97\ +\ 64\end{array}}{\space }$

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left.

Let's add the digits in the ones place:

Because the sum is greater than , we have to carry the to the tens place. So far, your work should look like the following:

Next, we add the numbers in the tens position, including the that was carried over:

Let's add the digits in the tens place:

Your final answer should be

Compare your answer with the correct one above

Question

Solve:

46

64

58

+ 14

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left.

Let's add the digits in the ones place:

Because the sum is greater than , we have to carry the to the tens place. So far, your work should look like the following:

Next, we add the numbers in the tens position, including the that was carried over:

Let's add the digits in the tens place:

Your final answer should be

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}18\48\68\ +\ 22\end{array}}{\space }$

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left.

Let's add the digits in the ones place:

Because the sum is greater than , we have to carry the to the tens place. So far, your work should look like the following:

Next, we add the numbers in the tens position, including the that was carried over:

Let's add the digits in the tens place:

Your final answer should be

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}43\36\11\ +\ 56\end{array}}{\space }$

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left.

Let's add the digits in the ones place:

Because the sum is greater than , we have to carry the to the tens place. So far, your work should look like the following:

Next, we add the numbers in the tens position, including the that was carried over:

Let's add the digits in the tens place:

Your final answer should be

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}53\11\66\ +\ 47\end{array}}{\space }$

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left.

Let's add the digits in the ones place:

Because the sum is greater than , we have to carry the to the tens place. So far, your work should look like the following:

Next, we add the numbers in the tens position, including the that was carried over:

Let's add the digits in the tens place:

Your final answer should be

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}87\81\90\ +\ 86\end{array}}{\space }$

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left.

Let's add the digits in the ones place:

Because the sum is greater than , we have to carry the to the tens place. So far, your work should look like the following:

Next, we add the numbers in the tens position, including the that was carried over:

Let's add the digits in the tens place:

Your final answer should be

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}80\99\42\ +\ 82\end{array}}{\space }$

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left.

Let's add the digits in the ones place:

Because the sum is greater than , we have to carry the to the tens place. So far, your work should look like the following:

Next, we add the numbers in the tens position, including the that was carried over:

Let's add the digits in the tens place:

Your final answer should be

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}48\21\17\ +\ 46\end{array}}{\space }$

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left.

Let's add the digits in the ones place:

Because the sum is greater than , we have to carry the to the tens place. So far, your work should look like the following:

Next, we add the numbers in the tens position, including the that was carried over:

Let's add the digits in the tens place:

Your final answer should be

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}36\20\25\ +\ 12\end{array}}{\space }$

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left.

Let's add the digits in the ones place:

Because the sum is greater than , we have to carry the to the tens place. So far, your work should look like the following:

Next, we add the numbers in the tens position, including the that was carried over:

Let's add the digits in the tens place:

Your final answer should be

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}89\30\56\ +\ 11\end{array}}{\space }$

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left.

Let's add the digits in the ones place:

Because the sum is greater than , we have to carry the to the tens place. So far, your work should look like the following:

Next, we add the numbers in the tens position, including the that was carried over:

Let's add the digits in the tens place:

Your final answer should be

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}97\13\98\ +\ 15\end{array}}{\space }$

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left.

Let's add the digits in the ones place:

Because the sum is greater than , we have to carry the to the tens place. So far, your work should look like the following:

Next, we add the numbers in the tens position, including the that was carried over:

Let's add the digits in the tens place:

Your final answer should be

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}81\39\82\ +\ 91\end{array}}{\space }$

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left.

Let's add the digits in the ones place:

Because the sum is greater than , we have to carry the to the tens place. So far, your work should look like the following:

Next, we add the numbers in the tens position, including the that was carried over:

Let's add the digits in the tens place:

Your final answer should be

Compare your answer with the correct one above

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