Power - College Physics

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Question

A resistive heating element can be modeled as a resistor connected across the terminals of a battery.

If the battery is selected to be , what should the resistance of the heating element be if the radiated power is to total ?

Answer

We are asked to calculate the power dissipated through a resistor connected to a battery. We know that . Substituting the values given above, . Solving for R yields .

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Question

What is the RMS voltage of a peak-to-peak AC current?

Answer

This question requires two steps: the first is to calculate the peak voltage of the AC current, and the second requires conversion of the peak voltage to an RMS voltage. We are told that the current is peak-to-peak. Thus, the peak voltage is half of this, or . By definition, to convert peak voltage to RMS voltage, we must divide the peak voltage by :

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Question

A battery is connected to two light bulbs that are arrange in parallel. What is the total power dissipated by the light bulbs?

Answer

The power dissipated in each light bulb is . Since there are two light bulbs, the total power dissipated is

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