Reactants and Products of Lipid Catabolism - Biochemistry

Card 0 of 9

Question

How many rounds of beta oxidation will a fatty acid with a hydrocarbon tail that is 20 carbons long undergo? What are the products?

Answer

Each round of beta oxidation yields one molecule of acetyl-CoA (along with one molecule of FADH2 and one molecule of NADH). Both electron carriers feed into the electron transport chain, ultimately yielding ATP via chemiosmosis. Since the organic product of beta oxidation (acetyl-CoA) contains two carbons, nine rounds of beta oxidation are required to fully oxidize a fatty acid with a 20-carbon hydrocarbon tail. Recognize that it is NOT 10 rounds because the last round (9th) will cut the now 4-carbon hydrocarbon tail, yielding two acetyl-CoA molecules. As a rule, a fatty acid with a hydrocarbon tail of of carbons undergoes rounds of beta oxidation to be full oxidized.

Overall, for a fatty acid with 20 carbons in its hydrocarbon chain, 9 rounds of beta oxidation yielding 10 molecules of acetyl-CoA constitutes complete oxidation.

Compare your answer with the correct one above

Question

Which of the following is not a product of beta oxidation of fatty acids?

Answer

One round of beta oxidation of fatty acids removes 2 carbons off the fatty acid chain at a time, yielding acetyl-CoA as well as and (from the 2 oxidation steps). ATP is not a direct product of beta oxidation, however the acetyl-CoA and reduced coenzymes will provide ATP via Krebs cycle and electron transport.

Compare your answer with the correct one above

Question

In plants, a cycle known as the glyoxylate cycle exists, which allows plants to synthesize carbohydrates from fats. This is how fat-rich seeds are anabolized to produce carbohydrates in plants.

Even though the glyoxylate cycle does not exist in humans, there is one molecule that is used in gluconeogenesis that comes from -oxidation of fatty acids. Which molecule is this?

Answer

-oxidation of fatty acids yields large quantities of acetyl-CoA, all of which enters the citric acid cycle. The only intermediate in the citric acid cycle that can form back into glucose is oxaloacetate. It can be turned into phosphoenolpyruvate via phosphoenolpyruvate carboxykinase.

Compare your answer with the correct one above

Question

What is the first step of the beta oxidation of fatty acids?

Answer

In the first step of beta oxidation the enzyme acyl-CoA dehydrogenase forms a trans-double bond between the two carbons at the site that will eventually be cleaved.

Compare your answer with the correct one above

Question

On average, how many ATP and GTP molecules can be generated from an eighteen-carbon fatty acid?

Answer

First, one must know what the products of one cycle of the beta oxidation pathway are. Each cycle yields , , 1 acetyl-CoA, and a fatty acyl-CoA molecule 2 carbons shorter than the original.

Therefore, an eighteen-carbon fatty acyl-CoA input can go through the beta oxidation cycle 8 times (the last round only a 2 carbon acetyl CoA remains, which cannot enter the beta oxidation pathway again). That means there are molecules, 9 acetyl-CoA molecules, and molecules that can be generated from an eighteen-carbon fatty acyl-CoA.

It may be confusing to understand why there are only and molecules and 9 acetyl-CoA, but if one is solving a problem such as this for the first time, go through and draw out the products following each round of the beta oxidation cycle.

2.5 ATP on average can be formed from each molecule, and 1.5 ATP from each molecule through the electron transport chain. 10 ATP can be formed in total from one acetyl-CoA entering into the Krebs cycle (by the products of and ), along with one GTP molecule.

Therefore:

If taken into consideration, 2 ATP are needed to activate a fatty acid and allow it to enter into the mitochondria via the enzyme acyl-CoA synthetase.

Therefore, the toTal net yield is

For a quick reference, the following equations can be used:

Where is number of carbons of aneven numbered fatty acid chain.

Compare your answer with the correct one above

Question

How many molecules of acetyl-CoA can be expected to be produced from the beta-oxidation of palmitic acid?

Note: Palmitic acid is a saturated fatty acid containing sixteen carbon atoms.

Answer

For each round of beta-oxidation, two carbon atoms are removed from the fatty acid chain. These two carbon atoms come off of the chain in the form of acetyl-CoA. Additionally, high energy electron carriers in the form of NADH and are also produced, thus making beta-oxidation a process that liberates a great deal of energy.

Since the fatty acid that we're starting with has a total of carbon atoms, we can expect there to be a total of acetyl-CoA molecules produced, since each of these contains two carbons from the fatty acid.

Compare your answer with the correct one above

Question

Which of the following molecules is/are the product(s) at the end of normal beta oxidation of a fatty acid?

Answer

During beta oxidation of fatty acids, carbons are removed from the fatty acid chain two at a time. So when a fatty acid is composed of an even number of carbons (as most are) 4 carbons will be left at the end. This will be cleaved into two separate 2 carbon molecules - two acetyl-CoA molecules.

Compare your answer with the correct one above

Question

Which of the following molecules is/are produced at the end of beta oxidation of a fatty acid with an odd number of carbons in its carbon chain?

Answer

During beta-oxidation of fatty acids, carbons are removed from the fatty acid chain two at a time. So when a fatty acid is composed of an odd number of carbons, 5 carbons will be left at the end. This will be cleaved into two separate molecules - one with 3 carbons and one with 2 carbons. This is one acetyl-CoA molecule (2 carbons) and one propionyl-CoA molecule (3 carbons).

Compare your answer with the correct one above

Question

During beta oxidation, what is the end product of a fatty acid with an odd number of carbons?

Answer

Fatty acids with an odd number of carbons are more common in plants and marine organisms than they are in mammals. When humans consume these organisms in their diets, they must metabolize them through beta oxidation. The end product of this reaction is propionyl-CoA rather than acetyl-CoA, which is formed during cleavage of two-carbon segments (fatty acids with an even number of carbons). Before entering the Krebs cycle, the propionyl-CoA must be transformed into succinyl-CoA.

Compare your answer with the correct one above

Tap the card to reveal the answer