How to simulate random behavior - AP Statistics
Card 0 of 2
Which of the following is NOT a discrete random variable?
Which of the following is NOT a discrete random variable?
By definition, a discrete random variable is a random variable whose values can be "counted" one by one. A continuous random variable is a random variable that can take any value on a certain interval. Of these choices, the number of lip products, the amount of money, and the number of midterms taken are all discrete random variables, as the respective values can be counted; however, the time taken to watch the first four seasons of a TV show is a continuous random variable, as not everyone will take the same amount of time to watch all those episodes (i.e. some might fastf-orward/replay parts of episodes).
By definition, a discrete random variable is a random variable whose values can be "counted" one by one. A continuous random variable is a random variable that can take any value on a certain interval. Of these choices, the number of lip products, the amount of money, and the number of midterms taken are all discrete random variables, as the respective values can be counted; however, the time taken to watch the first four seasons of a TV show is a continuous random variable, as not everyone will take the same amount of time to watch all those episodes (i.e. some might fastf-orward/replay parts of episodes).
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Police estimate that 85% of drivers do not text and drive. They set up a safety roadblock at a busy intersection to check for this infraction.
What is the probability that the first texter is in the thirteenth car stopped?
Police estimate that 85% of drivers do not text and drive. They set up a safety roadblock at a busy intersection to check for this infraction.
What is the probability that the first texter is in the thirteenth car stopped?
This question pertains to the concept of Geometric Probability Distribution, which states that the probability of 
trials until the first success is as follows:
In this equation, 
is the probability of success (in this case, a driver caught texting), and 
is the probability of failure.
In this particular problem, 
, and 
. To calculate the probability of finding that the first driver caught texting is in the thirteenth car stopped, we can calculate 
. The final answer is 
.
This question pertains to the concept of Geometric Probability Distribution, which states that the probability of
In this equation,
In this particular problem,
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