Magnification - AP Physics 2
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An object 
tall is 
from a mirror. If the image distance is 
from the mirror, what is the image height?
An object
The Magnification Equation is as follows:
The negative on the last part is very important. If you don't include it (and it's easy to forget), you will get the wrong answer.
We'll use the parts without 
for our problem. We want 
, so we just need to multiply both sides by 
.
Now, we can plug in our numbers.
Therefore, the image height is 
.
The Magnification Equation is as follows:
The negative on the last part is very important. If you don't include it (and it's easy to forget), you will get the wrong answer.
We'll use the parts without
Now, we can plug in our numbers.
Therefore, the image height is
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You have a concave mirror and a candle. The candle is 
tall, and the image is 
tall. What is the the magnification of the mirror?
You have a concave mirror and a candle. The candle is
The magnification equation is
where 
is the height of the image, and 
is the height of the object. We can plug these given values into the equation.
The magnification is a scalar value, so it's unitless. We can verify this by examining what goes into the equation. Both heights have the same units, which cancel, so that leaves us with no units.
The magnification equation is
where
The magnification is a scalar value, so it's unitless. We can verify this by examining what goes into the equation. Both heights have the same units, which cancel, so that leaves us with no units.
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The image produced by a concave mirror is at 
, and the magnification is 
. What is the object distance?
The image produced by a concave mirror is at
The equation for magnification is
We're given the image distance and the magnification, so we'd use the second equality.
Now, we can plug in our numbers.
The negative in front of the equation is very important. If you forget it, the answer will be incorrect.
The distance from the mirror to the object is 
. Note that the object distance is always positive.
The equation for magnification is
We're given the image distance and the magnification, so we'd use the second equality.
Now, we can plug in our numbers.
The negative in front of the equation is very important. If you forget it, the answer will be incorrect.
The distance from the mirror to the object is
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An object of height 
object is placed 
in front of a convex mirror that has a radius of curvature of 
. Determine the magnification of the image.
An object of height
Using the relationship:
Where:
is the object distance from the mirror
is the image distance from the mirror
is the focal length of the mirror
is the radius of curvature of the mirror
Plugging in values:
Solving for 
:
Using the equation for magnification:
Where:
is magnification
Using the relationship:
Where:
Plugging in values:
Solving for
Using the equation for magnification:
Where:
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You are passing a ray of light through a thin tank of alcohol to determine properties. Assume that the light ray is not effected by the tank's exterior. You find that if a piece of white paper is put underneath the alcohol tank, there is an image on the metal.
Assuming that the image is the size of 
and is actually a picture of a tree of size 
. What can we say about the magnification of this alcohol solution?
You are passing a ray of light through a thin tank of alcohol to determine properties. Assume that the light ray is not effected by the tank's exterior. You find that if a piece of white paper is put underneath the alcohol tank, there is an image on the metal.
Assuming that the image is the size of
To determine magnification, we simply divide the object length from the image length.
The negative sign is used to designate that the image is real.
To determine magnification, we simply divide the object length from the image length.
The negative sign is used to designate that the image is real.
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