Electromagnetic Spectrum and Radiation - AP Physics 2

Card 0 of 3

Question

Determine the frequency of orange light, $\lambda=605nm$ .

Answer

Using

$c=\lambda* u$

Converting to and plugging in values

$3.0010^8=60510^{-9}* u$

$u=4.96*10^{14}Hz$

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Question

Determine the photon energy of orange light, $\lambda=605nm$ .

Answer

Using

$E=\frac{hc}{\lambda}$

is the photon energy

is Plank's constant, $6.62610^{-34}Js$

is the speed of light, $3.0010^8\frac{m}{s}$

$\lambda$ is the wavelength

Converting to and plugging in values:

$E=\frac{6.62610^{-34}3.0010^{8}}{60510^{-9}}$

$E=3.2910^{-19}J$

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Question

A beam of light is traveling at approximately $10\frac{m}{s}$ in a very dense medium. Given that the frequency of the light beam is , what is the wavelength of the light beam? Suppose that the speed of light in a vacuum is .

Answer

The wavelength of the light beam doesn't depend on the speed through the medium. As such, as can solve for wavelength $\lambda$ by simply solving:

$\lambda f=c$

Where is frequency and is the speed of light in a vacuum.

$\lambda=\frac{c}{f}=\frac{310^8 \frac{m}{s}}{100\frac{1}{s}}=310^6m$

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