AP Physics 2 › Capacitors and Electric Fields
A capacitor is placed in series with a battery. The plates are
apart and each have a
surface area. Determine the charge on the positive plate.
In the given circuit, the capacitor is made of two parallel circular plates of radius that are
apart. If
is equal to
, determine the electric field between the plates.
A parallel-plate capacitor is connected to a constant voltage source. If the distance between the plates of this capacitor is
and the capacitor holds a charge of
, what is the value of the electric field between the plates of this capacitor?
If , each plate of the capacitor has surface area
, and the plates are
apart, determine the electric field between the plates.
Imagine a capacitor with a magnitude of charge Q on either plate. This capacitor has area A, separation distance D, and is connected to a battery of voltage V. If some external agent pulls the capacitor apart such that D doubles, did the electric field, E, stored in the capacitor increase, decrease or stay the same?
If , each plate of the capacitor has surface area
, and the plates are
apart, determine the excess charge on the positive plate.
A parallel plate capacitor with a separation of and surface area
is in series with a
battery. How will the electric field in the capacitor change if the separation is doubled?
Imagine a capacitor with a magnitude of charge Q on either plate. This capacitor has area A, separation distance D, and is not connected to a battery of voltage V. If some external agent pulls the capacitor apart such that D doubles, did the electric field, E, stored in the capacitor increase, decrease or stay the same?
A parallel plate capacitor with a separation of and surface area
is in series with a
battery. How will the electric field in the capacitor change if a second
battery is added in series?
Consider the given diagram. If , each plate of the capacitor has surface area
, and the plates at
apart, determine the electric field between the plates.