Card 0 of 20
How is the graph of different from the graph of
?
Almost all transformed functions can be written like this:
where is the parent function. In this case, our parent function is
, so we can write
this way:
Luckily, for this problem, we only have to worry about and
.
represents the vertical stretch factor of the graph.
represents the vertical translation of the graph.
For this problem, is 4 and
is -3, causing vertical stretch by a factor of 4 and a vertical translation down 3 units.
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Which of the following represents a standard parabola shifted up by 2 units?
Begin with the standard equation for a parabola: .
Vertical shifts to this standard equation are represented by additions (upward shifts) or subtractions (downward shifts) added to the end of the equation. To shift upward 2 units, add 2.
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Which of the following transformation flips a parabola vertically, doubles its width, and shifts it up by 3?
Begin with the standard equation for a parabola: .
Inverting, or flipping, a parabola refers to the sign in front of the coefficient of the . If the coefficient is negative, then the parabola opens downward.
The width of the parabola is determined by the magnitude of the coefficient in front of . To make a parabola wider, use a fractional coefficient. Doubling the width indicates a coefficient of one-half.
Vertical shifts are represented by additions (upward shifts) or subtractions (downward shifts) added to the end of the equation. To shift upward 3 units, add 3.
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Which of the following shifts a parabola six units to the right and five downward?
Begin with the standard equation for a parabola: .
Vertical shifts to this standard equation are represented by additions (upward shifts) or subtractions (downward shifts) added to the end of the equation. To shift downward 5 units, subtract 5.
Horizontal shifts are represented by additions (leftward shifts) or subtractions (rightward shifts) within the parenthesis of the term. To shift 6 units to the right, subtract 6 within the parenthesis.
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Which of the following transformations represents a parabola shifted to the right by 4 and halved in width?
Begin with the standard equation for a parabola: .
Horizontal shifts are represented by additions (leftward shifts) or subtractions (rightward shifts) within the parenthesis of the term. To shift 4 units to the right, subtract 4 within the parenthesis.
The width of the parabola is determined by the magnitude of the coefficient in front of . To make a parabola narrower, use a whole number coefficient. Halving the width indicates a coefficient of two.
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Which of the following transformations represents a parabola that has been flipped vertically, shifted to the right 12, and shifted downward 4?
Begin with the standard equation for a parabola: .
Horizontal shifts are represented by additions (leftward shifts) or subtractions (rightward shifts) within the parenthesis of the term. To shift 12 units to the right, subtract 12 within the parenthesis.
Inverting, or flipping, a parabola refers to the sign in front of the coefficient of the . If the coefficient is negative, then the parabola opens downward.
Vertical shifts are represented by additions (upward shifts) or subtractions (downward shifts) added to the end of the equation. To shift downward 4 units, subtract 4.
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Which of the following transformations represents a parabola that has been shifted 4 units to the left, 5 units down, and quadrupled in width?
Begin with the standard equation for a parabola: .
Horizontal shifts are represented by additions (leftward shifts) or subtractions (rightward shifts) within the parenthesis of the term. To shift 4 units to the left, add 4 within the parenthesis.
The width of the parabola is determined by the magnitude of the coefficient in front of . To make a parabola wider, use a fractional coefficient. Doubling the width indicates a coefficient of one-fourth.
Vertical shifts are represented by additions (upward shifts) or subtractions (downward shifts) added to the end of the equation. To shift downward 5 units, subtract 5.
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If the function is shifted left 2 units, and up 3 units, what is the new equation?
Shifting left 2 units will change the y-intercept from
to
.
The new equation after shifting left 2 units is:
Shifting up 3 units will add 3 to the y-intercept of the new equation.
The answer is:
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Transformations
Where will the point be located after the following transformations?
Where will the point be located after the following transformations?
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If , what is
?
It helps to evaluate the expression algebraically.
. Any time you multiply a function by a -1, you reflect it over the x axis. It helps to graph for verification.
This is the graph of
and this is the graph of
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If , what is
?
Algebraically, .
This is a reflection across the y axis.
This is the graph of
And this is the graph of
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Find the equation of the linear function obtained by shifting the following linear function
along the x-axis 3 units to the left. State the y-intercept of
.
The transformation for a left shift along the x-axis for requires we add
to the argument of the function
.
The y-intercept of the linear function is
.
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If the function is linear and the function
is quadratic, then the function
is?
The linear function will have the form,
Where is the y-intercept and
is the slope; both are constant.
The quadratic function will have the form,
We are given that the function is defined,
we obtain another function that is also a quadratic function since and
are constants. Therefore,
is quadratic.
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Reflect across the x-axis, then reflect across
, and then shift this line up five units. What is the new equation?
Reflect across the x-axis will turn the equation to:
If we then reflect across
, the equation will become:
Shifting this line up five units means that we will add five to this equation.
The equation after all the transformations is:
The answer is:
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Shift down three units. What is the new equation?
The equation is currently in standard form. Rewrite the current equation in slope-intercept form. Subtract from both sides.
Since the graph is shifted downward three units, all we need to change is decrease the y-intercept by three. Subtract the right side by three.
The answer is:
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Reflect the line across the line
, and then reflect again across the line
. What is the new equation of this horizontal line?
The distance between and
is three units. If the line
is reflected across
, this means that the new line will also be three units away from
.
The equation of the line after this reflection is:
If this line is reflected again across the line , both lines are six units apart, and the reflection would mean that the line below line
is also six units apart.
Subtract six from line .
The equation of the line after the transformations is:
The answer is:
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If the function is shifted down two units and left four units, what is the new y-intercept?
If the graph was shifted two units down, only the y-intercept will change, and will decrease by two.
The new equation is:
If the graph was shifted left four units, the root will shift four units to the left, and the will need to be replaced with
.
The new y-intercept will be .
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Reflect the line across
, and shift the line down three units. What is the new equation?
The equations with an existing variable is incorrect because they either represent lines with slopes or vertical lines.
After the line is reflected across
, the line becomes
.
Shifting this line down three units mean that the line will have a vertical translation down three.
Subtract the equation by three.
The result is:
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Give the equation of the vertical asymptote of the graph of the equation .
Define . As an exponential function, this has a graph that has no vertical asymptote, as
is defined for all real values of
. In terms of
:
,
The graph of is a transformation of that of
- a horizontal shift (
), a vertical stretch (
), and a vertical shift (
) of the graph of
; none of these transformations changes the status of the function as one whose graph has no vertical asymptote.
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Give the equation of the horizontal asymptote of the graph of the equation
Define in terms of
,
It can be restated as the following:
The graph of has as its horizontal asymptote the line of the equation
. The graph of
is a transformation of that of
—a right shift of 2 units
, a vertical stretch
, and an upward shift of 5 units
. The right shift and the vertical stretch do not affect the position of the horizontal asymptote, but the upward shift moves the asymptote to the line of the equation
. This is the correct response.
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