Transformations - Algebra II

Card 0 of 20

Question

How is the graph of different from the graph of ?

Answer

Almost all transformed functions can be written like this:

where is the parent function. In this case, our parent function is , so we can write this way:

Luckily, for this problem, we only have to worry about and .

represents the vertical stretch factor of the graph.

  • If is less than 1, the graph has been vertically compressed by a factor of . It's almost as if someone squished the graph while their hands were on the top and bottom. This would make a parabola, for example, look wider.
  • If is greater than 1, the graph has been vertically stretched by a factor of . It's almost as if someone pulled on the graph while their hands were grasping the top and bottom. This would make a parabola, for example, look narrower.

represents the vertical translation of the graph.

  • If is positive, the graph has been shifted up units.
  • If is negative, the graph has been shifted down units.

For this problem, is 4 and is -3, causing vertical stretch by a factor of 4 and a vertical translation down 3 units.

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Question

Which of the following represents a standard parabola shifted up by 2 units?

Answer

Begin with the standard equation for a parabola: .

Vertical shifts to this standard equation are represented by additions (upward shifts) or subtractions (downward shifts) added to the end of the equation. To shift upward 2 units, add 2.

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Question

Which of the following transformation flips a parabola vertically, doubles its width, and shifts it up by 3?

Answer

Begin with the standard equation for a parabola: .

Inverting, or flipping, a parabola refers to the sign in front of the coefficient of the . If the coefficient is negative, then the parabola opens downward.

The width of the parabola is determined by the magnitude of the coefficient in front of . To make a parabola wider, use a fractional coefficient. Doubling the width indicates a coefficient of one-half.

Vertical shifts are represented by additions (upward shifts) or subtractions (downward shifts) added to the end of the equation. To shift upward 3 units, add 3.

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Question

Which of the following shifts a parabola six units to the right and five downward?

Answer

Begin with the standard equation for a parabola: .

Vertical shifts to this standard equation are represented by additions (upward shifts) or subtractions (downward shifts) added to the end of the equation. To shift downward 5 units, subtract 5.

Horizontal shifts are represented by additions (leftward shifts) or subtractions (rightward shifts) within the parenthesis of the term. To shift 6 units to the right, subtract 6 within the parenthesis.

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Question

Which of the following transformations represents a parabola shifted to the right by 4 and halved in width?

Answer

Begin with the standard equation for a parabola: .

Horizontal shifts are represented by additions (leftward shifts) or subtractions (rightward shifts) within the parenthesis of the term. To shift 4 units to the right, subtract 4 within the parenthesis.

The width of the parabola is determined by the magnitude of the coefficient in front of . To make a parabola narrower, use a whole number coefficient. Halving the width indicates a coefficient of two.

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Question

Which of the following transformations represents a parabola that has been flipped vertically, shifted to the right 12, and shifted downward 4?

Answer

Begin with the standard equation for a parabola: .

Horizontal shifts are represented by additions (leftward shifts) or subtractions (rightward shifts) within the parenthesis of the term. To shift 12 units to the right, subtract 12 within the parenthesis.

Inverting, or flipping, a parabola refers to the sign in front of the coefficient of the . If the coefficient is negative, then the parabola opens downward.

Vertical shifts are represented by additions (upward shifts) or subtractions (downward shifts) added to the end of the equation. To shift downward 4 units, subtract 4.

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Question

Which of the following transformations represents a parabola that has been shifted 4 units to the left, 5 units down, and quadrupled in width?

Answer

Begin with the standard equation for a parabola: .

Horizontal shifts are represented by additions (leftward shifts) or subtractions (rightward shifts) within the parenthesis of the term. To shift 4 units to the left, add 4 within the parenthesis.

The width of the parabola is determined by the magnitude of the coefficient in front of . To make a parabola wider, use a fractional coefficient. Doubling the width indicates a coefficient of one-fourth.

Vertical shifts are represented by additions (upward shifts) or subtractions (downward shifts) added to the end of the equation. To shift downward 5 units, subtract 5.

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Question

If the function is shifted left 2 units, and up 3 units, what is the new equation?

Answer

Shifting left 2 units will change the y-intercept from to .

The new equation after shifting left 2 units is:

Shifting up 3 units will add 3 to the y-intercept of the new equation.

The answer is:

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Question

Transformations

Where will the point be located after the following transformations?

  • Reflection about the x-axis
  • Translation up 3
  • Translation right 4

Answer

Where will the point be located after the following transformations?

  1. Reflection about the x-axis results in multiplying the y value by negative one thus .
  2. Translation up 3, means to add three to the y values which results in .
  3. Translation right 4, means to add four to the x value which will result in .

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Question

If , what is ?

Answer

It helps to evaluate the expression algebraically.

. Any time you multiply a function by a -1, you reflect it over the x axis. It helps to graph for verification.

This is the graph of

X 2

and this is the graph of

 x 2

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Question

If , what is ?

Answer

Algebraically, .

This is a reflection across the y axis.

This is the graph of

E x

And this is the graph of

E  x

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Question

Find the equation of the linear function obtained by shifting the following linear function along the x-axis 3 units to the left. State the y-intercept of .

Answer

The transformation for a left shift along the x-axis for requires we add to the argument of the function .

The y-intercept of the linear function is .

Plotproblem7

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Question

If the function is linear and the function is quadratic, then the function is?

Answer

The linear function will have the form,

Where is the y-intercept and is the slope; both are constant.

The quadratic function will have the form,

We are given that the function is defined,

we obtain another function that is also a quadratic function since and are constants. Therefore, is quadratic.

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Question

Reflect across the x-axis, then reflect across , and then shift this line up five units. What is the new equation?

Answer

Reflect across the x-axis will turn the equation to:

If we then reflect across , the equation will become:

Shifting this line up five units means that we will add five to this equation.

The equation after all the transformations is:

The answer is:

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Question

Shift down three units. What is the new equation?

Answer

The equation is currently in standard form. Rewrite the current equation in slope-intercept form. Subtract from both sides.

Since the graph is shifted downward three units, all we need to change is decrease the y-intercept by three. Subtract the right side by three.

The answer is:

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Question

Reflect the line across the line , and then reflect again across the line . What is the new equation of this horizontal line?

Answer

The distance between and is three units. If the line is reflected across , this means that the new line will also be three units away from .

The equation of the line after this reflection is:

If this line is reflected again across the line , both lines are six units apart, and the reflection would mean that the line below line is also six units apart.

Subtract six from line .

The equation of the line after the transformations is:

The answer is:

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Question

If the function is shifted down two units and left four units, what is the new y-intercept?

Answer

If the graph was shifted two units down, only the y-intercept will change, and will decrease by two.

The new equation is:

If the graph was shifted left four units, the root will shift four units to the left, and the will need to be replaced with .

The new y-intercept will be .

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Question

Reflect the line across , and shift the line down three units. What is the new equation?

Answer

The equations with an existing variable is incorrect because they either represent lines with slopes or vertical lines.

After the line is reflected across , the line becomes .

Shifting this line down three units mean that the line will have a vertical translation down three.

Subtract the equation by three.

The result is:

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Question

Give the equation of the vertical asymptote of the graph of the equation .

Answer

Define . As an exponential function, this has a graph that has no vertical asymptote, as is defined for all real values of . In terms of :

,

The graph of is a transformation of that of - a horizontal shift ( ), a vertical stretch ( ), and a vertical shift ( ) of the graph of ; none of these transformations changes the status of the function as one whose graph has no vertical asymptote.

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Question

Give the equation of the horizontal asymptote of the graph of the equation

Answer

Define in terms of ,

It can be restated as the following:

The graph of has as its horizontal asymptote the line of the equation . The graph of is a transformation of that of —a right shift of 2 units , a vertical stretch , and an upward shift of 5 units . The right shift and the vertical stretch do not affect the position of the horizontal asymptote, but the upward shift moves the asymptote to the line of the equation . This is the correct response.

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