Card 0 of 19
Simplify.
a. Begin by using the FOIL method to square (2x-2).
The resulting equation should be:
b. Distribute -5 to the expression inside the parentheses to get
c. Finish simplifying by combining like terms:
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Betty is working on increasing the number of minutes that she can run consecutively. Each time she goes for a jog she runs minutes longer than the previous time. She starts at
minutes per jog. If she runs
times per week, how long can she run after
weeks?
If Betty increases her time by 2 minutes 3 times a week, then she increases her time by a total of 6 minutes per week. We also know that she starts out running for 20 minutes. We can use this information to set up the equation in form as:
Here x is the number of weeks, and y is the number of minutes she can run at the end of each week. The question is asking for how many minutes she can run at the end of 2 weeks, so we plug in 2 for x:
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Brian places an order for pairs of socks and
belts at a total cost of
. Danny places an order at the same store for
pairs of socks and
belts, at a total of
. What is the cost for a single pair of socks and a single belt?
We can set up a system of equations to solve this problem. If we call the price of a single pair of socks "s" and a single belt "b" then we can set up the following equations:
The easiest way to solve this system would be to combine them in such a way that eliminates one of the variables. We can do this by multiplying the bottom equation by -2, then adding it to the top equation.
This simplifies to:
Now when we add it to the first equation, the s variables will cancel out:
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We can now solve for b, then plug that value into either one of the original equations.
Thus, we get that the cost of a belt, b, is 10 dollars and the cost of a pair of socks, s, is 5 dollars.
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They say it takes ,
hours of practice to become an expert at something. If Anna practices piano
times a week for
minutes and Maggie practices piano
times a week for
an hour, who will hit
,
hours first? How many weeks will it take each girl?
The number of hours that Anna practices per week can be found by:
If Anna practices for 4.5 hours per week, then the number of weeks it will take for her to reach 10,000 hours can by found by:
We can use the same process to find the number of hours that Maggie practices per week, and from there the number of weeks it will take her to reach 10,000 hours:
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Dave starts biking at miles per hour.
an hour later, his friend Mike starts biking after him from the same starting point at
miles per hour. How long does it take Mike to catch up to Dave?
The equation for Dave's distance after t hours can be written as:
Since Mike is biking for half an hour less than Dave, we can write his distance as:
We want to know how many hours it takes for Mike to catch up to Dave. In other words, we are looking for the time when they have traveled the same distance. So, we can set the equations for distance traveled equal to each other:
"t" is how long Dave bikes for until Mike catches up. "t-.5" is the amount of time that Mike bikes for, and that is what we are trying to find.
So, Mike bikes for 5/6 hours until he catches up with Dave.
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Simplify
Rearrange the terms by grouping like terms together:
then simplify:
.
Finally, move the numerical terms to the other side of the equation so that all of the like terms are together:
, then simplify:
.
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Simplify and solve:
Add on both sides of the equation.
Subtract four from both sides.
Divide by twelve on both sides.
Reduce.
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Simplify the equation and solve:
Use order of operations to expand the terms of the parenthesis first.
Rewrite the equation.
Simplify the left side of the equation.
Add ten on both sides of the equation.
Simplify.
The answer is:
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Solve for :
In order to isolate the variable, we will need to use order of operations to eliminate the parentheses and group the terms with an
variable to one side of the equation.
Distribute inside the parentheses.
Subtract five on both sides.
Add on both sides to move the negative
to the left side.
Take out a common factor of on the left side.
Divide by on both sides of the equation.
The answer is:
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Simplify:
To simplify the equation you need to divide the numerator (top) and denominator (bottom), so:
The numerator can be factored to:
The denominator can be factored to:
After reducing, we will get
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Simplify:
To simplify the equation you need to divide the numerator (top) and denominator (bottom), so:
The numerator can be factored to:
The denominator can be factored to:
After reducing, we will get
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Simplify:
To simplify:
1. Factor out from
and we will get:
2. Reduce the equation and the final solution is:
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Simplify the expression by combining like terms.
Simplify:
The original equation:
Now move all terms to one side, in this example, we will use the right side, but either side will work.
As you can see, we subtracted the terms on the left from both sides, effectively moving them to the other side.
Regrouping the terms so that "like terms" are together. Like terms are defined by having the same power of x.
Now, we add any terms that have like powers of x.
Now that all terms have been combined, we are finished. The equation is simplified.
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Solve for :
Multiply on both sides in order to eliminate the denominator.
Simplify both sides.
Use distribution to simplify both sides.
Isolate the term with only the y-variable by subtracting on both sides.
Simplify and reorder the right side by the order of power.
Divide by on both sides.
Simplify both sides.
The answer is:
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Simplify the equation:
In order to simplify and solve this equation, divide by six on both sides.
Simplify both sides.
Add three on both sides.
Simplify both sides.
Divide both sides by two.
The answer is:
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Simplify this expression:
Drop the parentheses and combine like terms.
and
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Simplify the following equation:
Subtract nine from both sides.
Divide both sides.
The answer is:
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Simplify the equation:
Add 38 on both sides.
Divide by two on both sides.
The equation becomes:
Add two on both sides.
Divide by three on both sides.
The answer is:
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Simplify the equation:
Start by squaring everything within the parentheses:
Now combine the fractions of degree 1 by finding a common denominator:
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