Graphing Hyperbolic Functions

Practice Questions

Algebra II › Graphing Hyperbolic Functions

Questions

$\small \frac{(x-3)^{2}}{4}-\frac{(y+2)^{2}}{9}=1$

In which direction does the graph of the above hyperbola open?

What are the vertices of this hyperbola?

$\frac{(x-2)^2}{4}-(y-5)^2=1$

Find the vertices of the following hyperbolic function:

$\frac{(x-2)^2}{16}-\frac{(y+3)^2}{9}=1$

Write the expression for this hyperbola in standard form:

${}y^2-6y-x^2+4x=-1}$