Card 0 of 12
What is the reference angle of an angle that measures 3510 in standard position?
3600 – 3510 = 90
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Which of the following is equivalent to cot(θ)sec(θ)sin(θ)
The first thing to do is to breakdown the meaning of each trig function, cot = cos/sin, sec = 1/cos, and sin = sin. Then put these back into the function and simplify if possible, so then (cos (Θ)/sin (Θ))*(1/cos (Θ))*(sin (Θ)) = (cos (Θ)*sin(Θ))/(sin (Θ)*cos(Θ)) = 1, since they all cancel out.
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In the unit circle above, if , what are the coordinates of
?
On the unit circle, (X,Y) = (cos Θ, sin Θ).
(cos Θ,sin Θ) = (cos 30º, sin 30º) = (√3 / 2 , 1 / 2)
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Simplify the following expression:
Convert cotΘ and secΘ to sinΘ and cosΘ and simplify the resulting complex fraction.
cotΘ = cosΘ secΘ = 1
sinΘ cosΘ
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Using trigonometry identities, simplify sinθcos2θ – sinθ
Factor the expression to get sinθ(cos2θ – 1).
The trig identity cos2θ + sin2θ = 1 can be reworked to becomes cos2θ – 1 = –sinθ resulting in the simplification of –sin3θ.
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Using trig identities, simplify sinθ + cotθcosθ
Cotθ can be written as cosθ/sinθ, which results in sinθ + cos2θ/sinθ.
Combining to get a single fraction results in (sin2θ + cos2θ)/sinθ.
Knowing that sin2θ + cos2θ = 1, we get 1/sinθ, which can be written as cscθ.
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Simplify sec4_Θ_ – tan4_Θ_.
Factor using the difference of two squares: _a_2 – _b_2 = (a + b)(a – b)
The identity 1 + tan2_Θ_ = sec2_Θ_ which can be rewritten as 1 = sec2_Θ_ – tan2_Θ_
So sec4_Θ_ – tan4_Θ_ = (sec2_Θ_ + tan2_Θ_)(sec2_Θ_ – tan2_Θ_) = (sec2_Θ_ + tan2_Θ_)(1) = sec2_Θ_ + tan2_Θ_
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Evaluate the expression below.
At , sine and cosine have the same value.
Cotangent is given by .
Now we can evaluate the expression.
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What is the reference angle for ?
The reference angle is between and
, starting on the positive
-axis and rotating in a counter-clockwise manor.
To find the reference angle, we subtract for each complete revolution until we get a positive number less than
.
is equal to two complete revolutions, plus a
angle. Since
is in Quadrant II, we subtract it from
to get our reference angle:
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What is the reference angle for ?
A reference angle is the smallest possible angle between a given angle measurement and the x-axis.
In this case, our angle lies in Quadrant I, so the angle is its own reference angle.
Thus, the reference angle for is
.
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What is the reference angle for ?
A reference angle is the smallest possible angle between a given angle measurement and the x-axis.
In this case, our angle lies in Quadrant III, so the angle is found by the formula
.
Thus, the reference angle for is
.
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What is the reference angle for ?
A reference angle is the smallest possible angle between a given angle measurement and the x-axis.
In this case, our angle lies in Quadrant II, so we can find our reference angle using the formula
.
Thus, the reference angle for is
.
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