How to find a missing side with tangent - ACT Math
Card 0 of 9
First, solve for side MN. Tan(30°) = MN/16√3, so MN = tan(30°)(16√3) = 16. Triangle LMN and MNO are similar as they're both 30-60-90 triangles, so we can set up the proportion LM/MN = MN/NO or 16√3/16 = 16/x. Solving for x, we get 9.24, so the closest whole number is 9.
First, solve for side MN. Tan(30°) = MN/16√3, so MN = tan(30°)(16√3) = 16. Triangle LMN and MNO are similar as they're both 30-60-90 triangles, so we can set up the proportion LM/MN = MN/NO or 16√3/16 = 16/x. Solving for x, we get 9.24, so the closest whole number is 9.
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Josh is at the state fair when he decides to take a helicopter ride. He looks down at about a 35 ° angle of depression and sees his house. If the helicopter was about 250 ft above the ground, how far does the helicopter have to travel to be directly above his house?
sin 35 ° = 0.57 cos 35 ° = 0.82 tan 35 ° = 0.70
Josh is at the state fair when he decides to take a helicopter ride. He looks down at about a 35 ° angle of depression and sees his house. If the helicopter was about 250 ft above the ground, how far does the helicopter have to travel to be directly above his house?
sin 35 ° = 0.57 cos 35 ° = 0.82 tan 35 ° = 0.70
The angle of depression is the angle formed by a horizontal line and the line of sight looking down from the horizontal.
This is a right triangle trig problem. The vertical distance is 250 ft and the horizontal distance is unknown. The angle of depression is 35°. We have an angle and two legs, so we use tan Θ = opposite ÷ adjacent. This gives an equation of tan 35° = 250/d where d is the unknown distance to be directly over the house.
The angle of depression is the angle formed by a horizontal line and the line of sight looking down from the horizontal.
This is a right triangle trig problem. The vertical distance is 250 ft and the horizontal distance is unknown. The angle of depression is 35°. We have an angle and two legs, so we use tan Θ = opposite ÷ adjacent. This gives an equation of tan 35° = 250/d where d is the unknown distance to be directly over the house.
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In a given right triangle 
, leg 
and 
. Using the definition of 
, find the length of leg 
. Round all calculations to the nearest hundredth.
In a given right triangle
In right triangles, SOHCAHTOA tells us that 
, and we know that 
and hypotenuse 
. Therefore, a simple substitution and some algebra gives us our answer.
Use a calculator or reference to approximate cosine.
Isolate the variable term.
Thus, 
.
In right triangles, SOHCAHTOA tells us that
Thus,
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Consider the triangle 
where 
. Find 
to the nearest decimal place.
Note: The triangle is not necessarily to scale
Consider the triangle where
Note: The triangle is not necessarily to scale
To solve this equation, it is best to remember the mnemonic SOHCAHTOA which translates to Sin = Opposite / Hypotenuse, Cosine = Adjacent / Hypotenuse, and Tangent = Opposite / Adjacent. Looking at the problem statement, we are given an angle and the side opposite of the angle, and we are looking for the side adjacent to the angle. Therefore, we will be using the TOA part of the mnemonic. Inserting the values given in the problem statement, we can write 
. Rearranging, we get 
. Therefore 
To solve this equation, it is best to remember the mnemonic SOHCAHTOA which translates to Sin = Opposite / Hypotenuse, Cosine = Adjacent / Hypotenuse, and Tangent = Opposite / Adjacent. Looking at the problem statement, we are given an angle and the side opposite of the angle, and we are looking for the side adjacent to the angle. Therefore, we will be using the TOA part of the mnemonic. Inserting the values given in the problem statement, we can write
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A piece of wire is tethered to a 
building at a 
angle. How far back is this wire from the bottom of said building? Round to the nearest inch.
A piece of wire is tethered to a
Begin by drawing out this scenario using a little right triangle:
Note importantly: We are looking for 
as the the distance to the bottomof the building. Now, this is not very hard at all! We know that the tangent of an angle is equal to the ratio of the side adjacent to that angle to the_opposite_ side of the triangle. Thus, for our triangle, we know:
Using your calculator, solve for 
:
This is 
. Now, take the decimal portion in order to find the number of inches involved.
Thus, rounded, your answer is 
feet and 
inches.
Begin by drawing out this scenario using a little right triangle:
Note importantly: We are looking for
Using your calculator, solve for
This is
Thus, rounded, your answer is
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What is the value of 
in the right triangle above? Round to the nearest hundredth.
What is the value of
Recall that the tangent of an angle is the ratio of the opposite side to the adjacent side of that triangle. Thus, for this triangle, we can say:
Solving for 
, we get:
or 
Recall that the tangent of an angle is the ratio of the opposite side to the adjacent side of that triangle. Thus, for this triangle, we can say:
Solving for
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In the right triangle shown above, let 
, 
, and 
. What is the value of 
Reduce all fractions.
In the right triangle shown above, let
First we need to find the value of 
. Use the mnemonic SOH-CAH-TOA which stands for:
.
Now we see at point 
we are looking for the opposite and adjacent sides, which are 
and 
respectively.
Thus we get that
and plugging in our values and reducing yields:
First we need to find the value of
Now we see at point
Thus we get that
and plugging in our values and reducing yields:
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In a given right triangle , leg 
and 
. Using the definition of 
, find the length of leg . Round all calculations to the nearest tenth.
In a given right triangle
In right triangles, SOHCAHTOA tells us that 
, and we know that 
and leg
. Therefore, a simple substitution and some algebra gives us our answer.
Use a calculator or reference to approximate cosine.
Isolate the variable term.
Thus, 
.
In right triangles, SOHCAHTOA tells us that
Thus,
Compare your answer with the correct one above
In a given right triangle , leg 
and 
. Using the definition of 
, find the length of leg . Round all calculations to the nearest tenth.
In a given right triangle
In right triangles, SOHCAHTOA tells us that 
, and we know that 
and hypotenuse 
. Therefore, a simple substitution and some algebra gives us our answer.
Use a calculator or reference to approximate cosine.
Isolate the variable term.
Thus, 
.
In right triangles, SOHCAHTOA tells us that
Thus,
Compare your answer with the correct one above