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Michelle makes a bank deposit of $1,500 at 4.2% annual interest, compounded monthly. Approximately how much money will be in Michelle’s bank account in 3 years?
The formula to use for compounded interest is
where P is the principal (original) amount, r is the interest rate (expressed in decimal form), n is the number of times per year the interest compounds, and t is the total number of years the money is left in the bank. In this problem, P=1,500, r=0.042, n=12, and t=3.
By plugging in, we find that Michelle will have about $1,701 at the end of three years.
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Jack has ,
to invest. If he invests two-thirds of it into a high-yield savings account with an annual interest rate of
, compounded quarterly, and the other third in a regular savings account at
simple interest, how much does Jack earn after one year?
First, break the problem into two segments: the amount Jack invests in the high-yield savings, and the amount Jack invests in the simple interest account (10,000 and 5,000 respectively).
Now let's work with the high-yield savings account. $10,000 is invested at an annual rate of 8%, compounded quarterly. We can use the compound interest formula to solve:
Plug in the values given:
Therefore, Jack makes $824.32 off his high-yield savings account. Now let's calculate the other interest:
Add the two together, and we see that Jack makes a total of, off of his investments.
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Ashley makes a bank deposit of at
annual interest, compounded monthly. About how many years will it take her deposit to grow to
?
The formula for compound interest is
where P is the principal (original) amount, r is the interest rate (in decimal form), n is the number of times per year the interest compounds, t is the time in years, and A is the final amount.
In this problem, we are solving for time, t. The given variables from the problem are:
Plugging these into the equation above, we get
This simplifies to
We can solve this by taking the natural log of both sides
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Alice wants to invest money such that in years she has
. The interest rate is
compounded quarterly. How much should she invest?
The formula for compound interest is
where P is the principal (original) amount, r is the interest rate (in decimal form), n is the number of times per year the interest compounds, t is the time in years, and A is the final amount.
In this problem, we are solving for the principal, P. The given variables from the problem are:
Plugging these into the equation above, we get
Solving for P, we get
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A five-year bond is opened with in it and an interest rate of
%, compounded annually. This account is allowed to compound for five years. Which of the following most closely approximates the total amount in the account after that period of time?
Each year, you can calculate your interest by multiplying the principle () by
. For one year, this would be:
For two years, it would be:
, which is the same as
Therefore, you can solve for a five year period by doing:
Using your calculator, you can expand the into a series of multiplications. This gives you
, which is closest to
.
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If a cash deposit account is opened with for a three year period at
% interest compounded once annually, which of the following is closest to the positive difference between the interest accrued in the third year and the interest accrued in the second year?
It is easiest to break this down into steps. For each year, you will multiply by to calculate the new value. Therefore, let's make a chart:
After year 1: ; Total interest:
After year 2: ; Let us round this to
; Total interest:
After year 3: ; Let us round this to
; Total interest:
Thus, the positive difference of the interest from the last period and the interest from the first period is:
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If an account has interest compounded annually at a rate of , what is the balance of the account after
years of compounding if the initial balance is
? Round to the nearest cent.
Recall that the equation for compounded interest (with annual compounding) is:
Where is the balance,
is the rate of interest, and
is the number of years.
Thus, for our data, we need to know:
This is approximately .
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If an account has interest compounded annually at a rate of , what is the balance of the account after
years of compounding if the initial balance is
? Round to the nearest cent.
Recall that the equation for compounded interest (with annual compounding) is:
Where is the balance,
is the rate of interest, and
is the number of years.
Thus, for our data, we need to know:
This is approximately .
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If an account has interest compounded quarterly at an annual rate of , what is the balance of the account after
years of compounding if the initial balance is
? Round to the nearest cent.
Recall that the equation for compounded interest (with quarterly compounding) is:
Where is the balance,
is the rate of interest,
is the number of years, and
is the number of times it is compounded per year.
Thus, for our data, we need to know:
This is approximately .
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An account is compounded at a given rate of interest annually for years. What is this rate if the beginning balance for the account was
and its ending balance
? Round to the nearest hundredth of a percent.
Recall that the equation for compounded interest (with annual compounding) is:
Where is the balance,
is the rate of interest, and
is the number of years.
Thus, for our data, we need to know:
Now, let's use for
. This gives us:
Using a logarithm, this can be rewritten:
This can be rewritten:
Now, you can solve for :
or
Now, finally you can rewrite this as:
Thus,
Now, round this to and recall that
Thus, and
or
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What is the value of the expression , given that
?
First, calculate the value of m by taking the two-thirds root of both m3/2 and 64, leaving m=16. Then solve the expression by plugging in 16 for m. This gives 162 + 3(16) = 256 + 48 = 304.
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A professional football player’s contract states that he will earn a salary of $1 million his first year. He would then have a 15% increase every year thereafter for the next 5 years. What would he make in his 6th and final season on the contract?
We can represent this as an exponential equation (just use million as a label and not a variable):
$1_m_ * (1.15)5 = $2.01_m_
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What digit appears in the units place when is multiplied out?
This problem is quite simple if you recall that the units place of powers of 2 follows a simple 4-step sequence.
Observe the first few powers of 2:
21 = 2, 22 = 4, 23 = 8, 24 = 16, 25 = 32, 26 = 64, 27 = 128, 28 = 256 . . .
The units place follows a sequence of 2, 4, 8, 6, 2, 4, 8, 6, etc. Thus, divide 102 by 4. This gives a remainder of 2.
The second number in the sequence is 4, so the answer is 4.
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If , then which of the following must also be true?
We know that the expression must be negative. Therefore one or all of the terms x7, y8 and z10 must be negative; however, even powers always produce positive numbers, so y8 and z10 will both be positive. Odd powers can produce both negative and positive numbers, depending on whether the base term is negative or positive. In this case, x7 must be negative, so x must be negative. Thus, the answer is x < 0.
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For which of the following values of n will (**–**3)n represent a real number between 0 and 1?
In order to transform a negative integer to a positive one, it must be taken to an even power, and to make it a fraction between 0 and 1, it must be taken to a negative power. The only choice that fits both criteria is -2.
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Evaluate
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Which of the following is a multiple of ?
For exponent problems like this, the easiest thing to do is to break down all the numbers that you have into their prime factors. Begin with the number given to you:
Now, in order for you to have a number that is a multiple of this, you will need to have at least in the prime factorization of the given number. For each of the answer choices, you have:
; This is the answer.
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Simplify the following:
Because the numbers involved in your fraction are so large, you are going to need to do some careful manipulating to get your answer. (A basic calculator will not work for something like this.) These sorts of questions almost always work well when you isolate the large factors and notice patterns involved. Let's first focus on the numerator. Go ahead and break apart the into its prime factors:
Note that these have a common factor of . Therefore, you can rewrite the numerator as:
Now, put this back into your fraction:
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Simplify the following:
With problems like this, it is always best to break apart your values into their prime factors. Let's look at the numerator and the denominator separately:
Numerator
Continuing the simplification:
Now, these factors have in common a . Factor this out:
Denominator
This is much simpler:
Now, return to your fraction:
Cancel out the common factors of :
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